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SRS Standard pair #516975173
details
property
value
status
complete
benchmark
size-12-alpha-3-num-21.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n143.star.cs.uiowa.edu
space
Waldmann_07_size12
run statistics
property
value
solver
MnM 3.18b
configuration
default
runtime (wallclock)
1.57642412186 seconds
cpu usage
4.566879707
max memory
8.64468992E8
stage attributes
key
value
output-size
1246
starexec-result
NO
output
/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 3-rule system { 0 ⟶ , 0 ⟶ 1 , 1 1 2 ⟶ 0 2 2 2 0 0 } Loop of length 15 starting with a string of length 8 using right expansion and the encoding { 0 ↦ a, 1 ↦ b, ... }: .a.bcccbcc rule a-> b at position 0 .b.bcccbcc rule bbc-> acccaa at position 0 .acccaa.ccbcc rule a-> b at position 4 .acccba.ccbcc rule a-> b at position 5 .acccbb.ccbcc rule bbc-> acccaa at position 4 .acccacccaa.cbcc rule a-> b at position 8 .acccacccba.cbcc rule a-> b at position 9 .acccacccbb.cbcc rule bbc-> acccaa at position 8 .acccacccacccaa.bcc rule a-> b at position 13 .acccacccacccab.bcc rule bbc-> acccaa at position 13 .acccacccacccaacccaa.c rule a-> b at position 13 .acccacccacccabcccaa.c rule a-> b at position 17 .acccacccacccabcccba.c rule a-> b at position 18 .acccacccacccabcccbb.c rule bbc-> acccaa at position 17 .acccacccacccabcccacccaa. rule a-> b at position 17 .acccacccacccabcccbcccaa.
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