details

property	value
status	complete
benchmark	size-12-alpha-3-num-70.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n074.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	MnM 3.18b
configuration	default
runtime (wallclock)	1.55522584915 seconds
cpu usage	4.518805261
max memory	9.21698304E8

stage attributes

key	value
output-size	6504
starexec-result	YES

output

/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES After renaming modulo the bijection { a ↦ 0, b ↦ 1, c ↦ 2 }, it remains to prove termination of the 5-rule system { 0 ⟶ , 0 0 ⟶ 1 , 1 ⟶ , 1 2 ⟶ 2 2 1 0 , 2 ⟶ } The system was reversed. After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2 }, it remains to prove termination of the 5-rule system { 0 ⟶ , 0 0 ⟶ 1 , 1 ⟶ , 2 1 ⟶ 0 1 2 2 , 2 ⟶ } Applying the dependency pairs transformation. Here, ↑ marks so-called defined symbols. After renaming modulo the bijection { (0,↑) ↦ 0, (0,↓) ↦ 1, (1,↑) ↦ 2, (2,↑) ↦ 3, (1,↓) ↦ 4, (2,↓) ↦ 5 }, it remains to prove termination of the 10-rule system { 0 1 ⟶ 2 , 3 4 ⟶ 0 4 5 5 , 3 4 ⟶ 2 5 5 , 3 4 ⟶ 3 5 , 3 4 ⟶ 3 , 1 →= , 1 1 →= 4 , 4 →= , 5 4 →= 1 4 5 5 , 5 →= } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 3 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 4 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 5 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ After renaming modulo the bijection { 0 ↦ 0, 1 ↦ 1, 2 ↦ 2, 3 ↦ 3, 4 ↦ 4, 5 ↦ 5 }, it remains to prove termination of the 8-rule system { 0 1 ⟶ 2 , 3 4 ⟶ 3 5 , 3 4 ⟶ 3 , 1 →= , 1 1 →= 4 , 4 →= , 5 4 →= 1 4 5 5 , 5 →= } The system was filtered by the following matrix interpretation of type E_J with J = {1,...,2} and dimension 2: 0 ↦ ⎛ ⎞ ⎜ 1 1 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 1 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ ⎜ 0 1 ⎟ ⎝ ⎠ 2 ↦ ⎛ ⎞ ⎜ 1 0 ⎟ popout

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