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SRS Standard pair #516975536
details
property
value
status
complete
benchmark
8.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n055.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.09100413322 seconds
cpu usage
6.94614965
max memory
8.0871424E8
stage attributes
key
value
output-size
1577
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(b(a(x1)))) -> b(a(a(b(x1)))) b(a(b(x1))) -> a(b(b(b(x1)))) Proof: Matrix Interpretation Processor: dim=4 interpretation: [1 0 0 0] [0 0 1 0] [b](x0) = [1 0 0 0]x0 [0 0 1 0] , [1 0 1 0] [1] [0 0 0 0] [0] [a](x0) = [0 1 0 1]x0 + [0] [0 0 0 0] [0] orientation: [2 0 2 0] [3] [2 0 2 0] [2] [0 0 0 0] [0] [0 0 0 0] [0] a(b(b(a(x1)))) = [2 0 2 0]x1 + [2] >= [2 0 2 0]x1 + [2] = b(a(a(b(x1)))) [0 0 0 0] [0] [0 0 0 0] [0] [2 0 0 0] [1] [2 0 0 0] [1] [0 0 2 0] [0] [0 0 0 0] [0] b(a(b(x1))) = [2 0 0 0]x1 + [1] >= [2 0 0 0]x1 + [0] = a(b(b(b(x1)))) [0 0 2 0] [0] [0 0 0 0] [0] problem: b(a(b(x1))) -> a(b(b(b(x1)))) String Reversal Processor: b(a(b(x1))) -> b(b(b(a(x1)))) Bounds Processor: bound: 0 enrichment: match automaton: final states: {1} transitions: f20() -> 2* a0(2) -> 3* b0(5) -> 1* b0(4) -> 5* b0(3) -> 4* 1 -> 4* problem: Qed
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