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SRS Standard pair #516975554
details
property
value
status
complete
benchmark
secr10.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n087.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
46.2816781998 seconds
cpu usage
183.106022547
max memory
1.599148032E9
stage attributes
key
value
output-size
15998
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(a(x1)) -> c(b(a(b(a(x1))))) b(a(b(x1))) -> b(x1) a(a(a(x1))) -> c(c(a(x1))) c(c(x1)) -> a(b(c(b(a(x1))))) a(c(a(x1))) -> c(c(a(x1))) c(a(c(x1))) -> a(a(c(x1))) Proof: String Reversal Processor: a(a(x1)) -> a(b(a(b(c(x1))))) b(a(b(x1))) -> b(x1) a(a(a(x1))) -> a(c(c(x1))) c(c(x1)) -> a(b(c(b(a(x1))))) a(c(a(x1))) -> a(c(c(x1))) c(a(c(x1))) -> c(a(a(x1))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [b](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [0] [a](x0) = [0 0 1]x0 + [1] [1 1 0] [0], [1 0 1] [0] [c](x0) = [0 1 0]x0 + [1] [1 1 0] [0] orientation: [1 1 1] [1] [1 0 1] [0] a(a(x1)) = [1 1 0]x1 + [1] >= [0 0 0]x1 + [1] = a(b(a(b(c(x1))))) [1 1 1] [1] [1 0 1] [0] [1 0 0] [1 0 0] b(a(b(x1))) = [0 0 0]x1 >= [0 0 0]x1 = b(x1) [0 0 0] [0 0 0] [2 2 1] [2] [2 2 1] [2] a(a(a(x1))) = [1 1 1]x1 + [2] >= [1 1 1]x1 + [2] = a(c(c(x1))) [2 2 1] [2] [2 2 1] [2] [2 1 1] [0] [1 1 0] [0] c(c(x1)) = [0 1 0]x1 + [2] >= [0 0 0]x1 + [1] = a(b(c(b(a(x1))))) [1 1 1] [1] [1 1 0] [0] [2 2 1] [2] [2 2 1] [2] a(c(a(x1))) = [1 1 1]x1 + [2] >= [1 1 1]x1 + [2] = a(c(c(x1))) [2 2 1] [2] [2 2 1] [2] [2 2 2] [2] [2 2 2] [2] c(a(c(x1))) = [1 1 0]x1 + [2] >= [1 1 0]x1 + [2] = c(a(a(x1))) [2 2 1] [2] [2 2 1] [2] problem: b(a(b(x1))) -> b(x1) a(a(a(x1))) -> a(c(c(x1))) c(c(x1)) -> a(b(c(b(a(x1))))) a(c(a(x1))) -> a(c(c(x1))) c(a(c(x1))) -> c(a(a(x1))) String Reversal Processor: b(a(b(x1))) -> b(x1) a(a(a(x1))) -> c(c(a(x1))) c(c(x1)) -> a(b(c(b(a(x1))))) a(c(a(x1))) -> c(c(a(x1))) c(a(c(x1))) -> a(a(c(x1))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [b](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [0] [a](x0) = [1 0 0]x0 + [1] [1 1 0] [0], [1 1 0] [0] [c](x0) = [0 0 1]x0 + [1] [1 1 0] [0] orientation: [1 0 0] [1 0 0] b(a(b(x1))) = [0 0 0]x1 >= [0 0 0]x1 = b(x1) [0 0 0] [0 0 0] [3 2 0] [2] [3 2 0] [2] a(a(a(x1))) = [2 1 0]x1 + [2] >= [2 1 0]x1 + [2] = c(c(a(x1))) [3 2 0] [2] [3 2 0] [2] [1 1 1] [1] [1 1 0] [0] c(c(x1)) = [1 1 0]x1 + [1] >= [1 1 0]x1 + [1] = a(b(c(b(a(x1))))) [1 1 1] [1] [1 1 0] [0]
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