details

property	value
status	complete
benchmark	16.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n094.star.cs.uiowa.edu
space	Zantema_06

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	3.01657795906 seconds
cpu usage	10.671043964
max memory	1.18278144E9

stage attributes

key	value
output-size	5455
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_ttt2 /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> b(x1) a(a(x1)) -> a(b(a(x1))) a(b(x1)) -> b(b(b(x1))) a(a(a(x1))) -> a(a(b(a(a(x1))))) a(a(b(x1))) -> a(b(b(a(b(x1))))) a(b(a(x1))) -> b(a(b(b(a(x1))))) a(b(b(x1))) -> b(b(b(b(b(x1))))) b(a(x1)) -> b(b(b(x1))) a(b(a(x1))) -> a(b(b(a(b(x1))))) b(a(a(x1))) -> b(a(b(b(a(x1))))) b(b(a(x1))) -> b(b(b(b(b(x1))))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [b](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [0] [a](x0) = [0 0 1]x0 + [1] [0 1 0] [0] orientation: [1 0 1] [0] [1 0 0] a(x1) = [0 0 1]x1 + [1] >= [0 0 0]x1 = b(x1) [0 1 0] [0] [0 0 0] [1 1 1] [0] [1 0 1] [0] a(a(x1)) = [0 1 0]x1 + [1] >= [0 0 0]x1 + [1] = a(b(a(x1))) [0 0 1] [1] [0 0 0] [0] [1 0 0] [0] [1 0 0] a(b(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = b(b(b(x1))) [0 0 0] [0] [0 0 0] [1 1 2] [1] [1 1 1] [0] a(a(a(x1))) = [0 0 1]x1 + [2] >= [0 0 0]x1 + [1] = a(a(b(a(a(x1))))) [0 1 0] [1] [0 0 0] [1] [1 0 0] [0] [1 0 0] [0] a(a(b(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = a(b(b(a(b(x1))))) [0 0 0] [1] [0 0 0] [0] [1 0 1] [0] [1 0 1] a(b(a(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 = b(a(b(b(a(x1))))) [0 0 0] [0] [0 0 0] [1 0 0] [0] [1 0 0] a(b(b(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 = b(b(b(b(b(x1))))) [0 0 0] [0] [0 0 0] [1 0 1] [1 0 0] b(a(x1)) = [0 0 0]x1 >= [0 0 0]x1 = b(b(b(x1))) [0 0 0] [0 0 0] [1 0 1] [0] [1 0 0] [0] a(b(a(x1))) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = a(b(b(a(b(x1))))) [0 0 0] [0] [0 0 0] [0] [1 1 1] [1 0 1] b(a(a(x1))) = [0 0 0]x1 >= [0 0 0]x1 = b(a(b(b(a(x1))))) [0 0 0] [0 0 0] [1 0 1] [1 0 0] b(b(a(x1))) = [0 0 0]x1 >= [0 0 0]x1 = b(b(b(b(b(x1))))) [0 0 0] [0 0 0] problem: a(x1) -> b(x1) a(a(x1)) -> a(b(a(x1))) a(b(x1)) -> b(b(b(x1))) a(a(b(x1))) -> a(b(b(a(b(x1))))) a(b(a(x1))) -> b(a(b(b(a(x1))))) a(b(b(x1))) -> b(b(b(b(b(x1))))) b(a(x1)) -> b(b(b(x1))) a(b(a(x1))) -> a(b(b(a(b(x1))))) b(a(a(x1))) -> b(a(b(b(a(x1))))) b(b(a(x1))) -> b(b(b(b(b(x1))))) String Reversal Processor: a(x1) -> b(x1) a(a(x1)) -> a(b(a(x1))) b(a(x1)) -> b(b(b(x1))) b(a(a(x1))) -> b(a(b(b(a(x1))))) a(b(a(x1))) -> a(b(b(a(b(x1))))) b(b(a(x1))) -> b(b(b(b(b(x1))))) a(b(x1)) -> b(b(b(x1))) a(b(a(x1))) -> b(a(b(b(a(x1))))) a(a(b(x1))) -> a(b(b(a(b(x1))))) a(b(b(x1))) -> b(b(b(b(b(x1))))) Matrix Interpretation Processor: dim=1 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS Standard