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SRS Standard pair #516977026
details
property
value
status
complete
benchmark
abaaaaaa-aaaaaaababaaab.srs.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n166.star.cs.uiowa.edu
space
Wenzel_16
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
2.32934999466 seconds
cpu usage
6.107406527
max memory
5.70474496E8
stage attributes
key
value
output-size
3565
starexec-result
YES
output
/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(a(a(x1)))))))) -> a(a(a(a(a(a(a(b(a(b(a(a(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(b(a(x1)))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(a(b(a(x1)))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(a(b(x))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(b(x))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(a(b(x))))))) -> b(a(a(a(b(a(b(a(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 247, 248, 249, 250, 251, 252, 253, 254, 255, 256, 257, 258, 259, 260, 261, 262, 263, 264, 265, 266, 267, 268, 269, 270, 271, 272 Node 247 is start node and node 248 is final node. Those nodes are connected through the following edges: * 247 to 249 labelled b_1(0)* 248 to 248 labelled #_1(0)* 249 to 250 labelled a_1(0)* 250 to 251 labelled a_1(0)* 251 to 252 labelled a_1(0)* 252 to 253 labelled b_1(0)* 253 to 254 labelled a_1(0)* 254 to 255 labelled b_1(0)* 255 to 256 labelled a_1(0)* 255 to 261 labelled b_1(1)* 256 to 257 labelled a_1(0)* 256 to 261 labelled b_1(1)* 257 to 258 labelled a_1(0)* 257 to 261 labelled b_1(1)* 258 to 259 labelled a_1(0)* 258 to 261 labelled b_1(1)* 259 to 260 labelled a_1(0)* 259 to 261 labelled b_1(1)* 260 to 248 labelled a_1(0)* 260 to 261 labelled b_1(1)* 261 to 262 labelled a_1(1)* 262 to 263 labelled a_1(1)* 263 to 264 labelled a_1(1)* 264 to 265 labelled b_1(1)* 265 to 266 labelled a_1(1)* 266 to 267 labelled b_1(1)* 267 to 268 labelled a_1(1)* 267 to 261 labelled b_1(1)* 268 to 269 labelled a_1(1)* 268 to 261 labelled b_1(1)* 269 to 270 labelled a_1(1)* 269 to 261 labelled b_1(1)* 270 to 271 labelled a_1(1)* 270 to 261 labelled b_1(1)* 271 to 272 labelled a_1(1)* 271 to 261 labelled b_1(1)* 272 to 248 labelled a_1(1)* 272 to 261 labelled b_1(1) ---------------------------------------- (6) YES
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