details

property	value
status	complete
benchmark	abaaaa-aaaaabaababaab.srs.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n146.star.cs.uiowa.edu
space	Wenzel_16

run statistics

property	value
solver	AProVE21
configuration	standard
runtime (wallclock)	2.35094499588 seconds
cpu usage	6.383032817
max memory	6.60533248E8

stage attributes

key	value
output-size	3417
starexec-result	YES

output

/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(a(a(a(x1)))))) -> a(a(a(a(a(b(a(a(b(a(b(a(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(b(a(a(b(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(b(a(a(b(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(b(x))))) -> b(a(a(b(a(b(a(a(b(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(b(x))))) -> b(a(a(b(a(b(a(a(b(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(b(x))))) -> b(a(a(b(a(b(a(a(b(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 525, 526, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538, 539, 540, 541, 542, 543, 544, 545, 546, 547, 548, 549, 550 Node 525 is start node and node 526 is final node. Those nodes are connected through the following edges: * 525 to 527 labelled b_1(0)* 526 to 526 labelled #_1(0)* 527 to 528 labelled a_1(0)* 528 to 529 labelled a_1(0)* 529 to 530 labelled b_1(0)* 530 to 531 labelled a_1(0)* 531 to 532 labelled b_1(0)* 532 to 533 labelled a_1(0)* 533 to 534 labelled a_1(0)* 534 to 535 labelled b_1(0)* 535 to 536 labelled a_1(0)* 535 to 539 labelled b_1(1)* 536 to 537 labelled a_1(0)* 536 to 539 labelled b_1(1)* 537 to 538 labelled a_1(0)* 537 to 539 labelled b_1(1)* 538 to 526 labelled a_1(0)* 538 to 539 labelled b_1(1)* 539 to 540 labelled a_1(1)* 540 to 541 labelled a_1(1)* 541 to 542 labelled b_1(1)* 542 to 543 labelled a_1(1)* 543 to 544 labelled b_1(1)* 544 to 545 labelled a_1(1)* 545 to 546 labelled a_1(1)* 546 to 547 labelled b_1(1)* 547 to 548 labelled a_1(1)* 547 to 539 labelled b_1(1)* 548 to 549 labelled a_1(1)* 548 to 539 labelled b_1(1)* 549 to 550 labelled a_1(1)* 549 to 539 labelled b_1(1)* 550 to 526 labelled a_1(1)* 550 to 539 labelled b_1(1) ---------------------------------------- (6) YES popout

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job log

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all output return to SRS Standard