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TRS Equational pair #516978273
details
property
value
status
complete
benchmark
AC28.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n119.star.cs.uiowa.edu
space
AProVE_AC_04
run statistics
property
value
solver
muterm 5.18
configuration
default
runtime (wallclock)
30.6263160706 seconds
cpu usage
30.450847896
max memory
6.26507776E8
stage attributes
key
value
output-size
6497
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR X Y Z x y) (THEORY (AC union)) (RULES max(union(singl(s(x)),singl(s(y)))) -> s(max(union(singl(x),singl(y)))) max(union(singl(x),union(Y,Z))) -> max(union(singl(x),singl(max(union(Y,Z))))) max(union(singl(x),singl(0))) -> x max(singl(x)) -> x union(empty,X) -> X ) Problem 1: Reduction Order Processor: -> Rules: max(union(singl(s(x)),singl(s(y)))) -> s(max(union(singl(x),singl(y)))) max(union(singl(x),union(Y,Z))) -> max(union(singl(x),singl(max(union(Y,Z))))) max(union(singl(x),singl(0))) -> x max(singl(x)) -> x union(empty,X) -> X ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [max](X) = X [union](X1,X2) = X1 + X2 + 1 [0] = 0 [empty] = 0 [s](X) = X + 1 [singl](X) = X Problem 1: Reduction Order Processor: -> Rules: max(union(singl(x),union(Y,Z))) -> max(union(singl(x),singl(max(union(Y,Z))))) max(union(singl(x),singl(0))) -> x max(singl(x)) -> x union(empty,X) -> X ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [max](X) = X [union](X1,X2) = X1 + X2 [0] = 2 [empty] = 0 [s](X) = 2.X [singl](X) = X Problem 1: Reduction Order Processor: -> Rules: max(union(singl(x),union(Y,Z))) -> max(union(singl(x),singl(max(union(Y,Z))))) max(singl(x)) -> x union(empty,X) -> X ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [max](X) = X [union](X1,X2) = X1 + X2 + 1 [0] = 0 [empty] = 2 [s](X) = 2.X [singl](X) = X Problem 1: Dependency Pairs Processor: -> FAxioms:
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