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TRS Conditional pair #516978693
details
property
value
status
complete
benchmark
272.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n092.star.cs.uiowa.edu
space
COPS
run statistics
property
value
solver
AProVE21
configuration
standard
runtime (wallclock)
2.4947988987 seconds
cpu usage
6.119252175
max memory
4.78674944E8
stage attributes
key
value
output-size
3911
starexec-result
YES
output
/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: c69e44bd14796315568835c1ffa2502984884775 mhark 20210624 unpublished Quasi decreasingness of the given CTRS could be proven: (0) CTRS (1) CTRSToQTRSProof [SOUND, 0 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 155 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Conditional term rewrite system: The TRS R consists of the following rules: lte(0, n) -> true lte(s(m), 0) -> false lte(s(m), s(n)) -> lte(m, n) insert(nil, m) -> cons(m, nil) ordered(nil) -> true ordered(cons(m, nil)) -> true The conditional TRS C consists of the following conditional rules: insert(cons(n, l), m) -> cons(m, cons(n, l)) <= lte(m, n) -> true insert(cons(n, l), m) -> cons(n, insert(l, m)) <= lte(m, n) -> false ordered(cons(m, cons(n, l))) -> ordered(cons(n, l)) <= lte(m, n) -> true ordered(cons(m, cons(n, l))) -> false <= lte(m, n) -> false ---------------------------------------- (1) CTRSToQTRSProof (SOUND) The conditional rules have been transormed into unconditional rules according to [CTRS,AAECCNOC]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: insert(cons(n, l), m) -> U1(lte(m, n), n, l, m) U1(false, n, l, m) -> cons(n, insert(l, m)) U1(true, n, l, m) -> cons(m, cons(n, l)) ordered(cons(m, cons(n, l))) -> U2(lte(m, n), n, l) U2(true, n, l) -> ordered(cons(n, l)) U2(false, n, l) -> false lte(0, n) -> true lte(s(m), 0) -> false lte(s(m), s(n)) -> lte(m, n) insert(nil, m) -> cons(m, nil) ordered(nil) -> true ordered(cons(m, nil)) -> true Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: insert/2(YES,YES) cons/2(YES,YES) U1/4(YES,YES,YES,YES) lte/2(YES,YES) false/0) true/0) ordered/1)YES( U2/3(YES,YES,YES) 0/0) s/1)YES( nil/0) Quasi precedence: [insert_2, U1_4, nil] > [true, 0] > [cons_2, lte_2, U2_3] > false Status: insert_2: [1,2] cons_2: [2,1] U1_4: [3,4,1,2] lte_2: [2,1] false: multiset status true: multiset status U2_3: [3,2,1]
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