details

property	value
status	complete
benchmark	jones1.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n027.star.cs.uiowa.edu
space	Mixed_TRS

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.427439928055 seconds
cpu usage	0.64189403
max memory	1.39886592E8

stage attributes

key	value
output-size	3251
starexec-result	"YES"

output

/export/starexec/sandbox2/solver/bin/starexec_run_ttt2 /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: rev(ls) -> r1(ls,empty()) r1(empty(),a) -> a r1(cons(x,k),a) -> r1(k,cons(x,a)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [0] [empty] = [0] [1], [1 0 0] [1 0 0] [1] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [1] [0 0 0] [0 1 1] [0], [1 0 1] [0] [rev](x0) = [1 1 1]x0 + [0] [1 0 0] [1], [1 0 1] [1 0 0] [r1](x0, x1) = [1 0 0]x0 + [0 1 0]x1 [1 0 0] [0 1 1] orientation: [1 0 1] [0] [1 0 1] [0] rev(ls) = [1 1 1]ls + [0] >= [1 0 0]ls + [0] = r1(ls,empty()) [1 0 0] [1] [1 0 0] [1] [1 0 0] [1] r1(empty(),a) = [0 1 0]a + [0] >= a = a [0 1 1] [0] [1 0 0] [1 1 1] [1 0 0] [1] [1 0 0] [1 0 1] [1 0 0] [1] r1(cons(x,k),a) = [0 1 0]a + [1 0 0]k + [1 0 0]x + [1] >= [0 0 0]a + [1 0 0]k + [0 0 0]x + [1] = r1(k,cons(x,a)) [0 1 1] [1 0 0] [1 0 0] [1] [0 1 1] [1 0 0] [0 0 0] [1] problem: rev(ls) -> r1(ls,empty()) r1(cons(x,k),a) -> r1(k,cons(x,a)) Matrix Interpretation Processor: dim=3 interpretation: [0] [empty] = [0] [0], [1 0 0] [1 0 0] [0] [cons](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 1] [1], [1 0 1] [rev](x0) = [0 0 0]x0 [0 0 0] , [1 0 1] [1 0 0] [r1](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] orientation: [1 0 1] [1 0 1] rev(ls) = [0 0 0]ls >= [0 0 0]ls = r1(ls,empty()) [0 0 0] [0 0 0] [1 0 0] [1 0 1] [1 0 0] [1] [1 0 0] [1 0 1] [1 0 0] r1(cons(x,k),a) = [0 0 0]a + [0 0 0]k + [0 0 0]x + [0] >= [0 0 0]a + [0 0 0]k + [0 0 0]x = r1(k,cons(x,a)) [0 0 0] [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0 0 0] problem: rev(ls) -> r1(ls,empty()) Matrix Interpretation Processor: dim=3 interpretation: [0] [empty] = [1] [0], [1 0 0] [1] [rev](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [1 0 0] [r1](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 1 0] orientation: [1 0 0] [1] [1 0 0] [0] rev(ls) = [0 0 0]ls + [0] >= [0 0 0]ls + [0] = r1(ls,empty()) [0 0 0] [1] [0 0 0] [1] problem: Qed popout

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all output return to TRS Standard