/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: half(0()) -> 0() half(s(0())) -> 0() half(s(s(x))) -> s(half(x)) s(log(0())) -> s(0()) log(s(x)) -> s(log(half(s(x)))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1] [log](x0) = [0 1 0]x0 + [0] [0 1 0] [1], [1 0 0] [s](x0) = [0 1 0]x0 [0 0 0] , [1 0 0] [half](x0) = [0 1 0]x0 [0 0 0] , [0] [0] = [0] [0] orientation: [0] [0] half(0()) = [0] >= [0] = 0() [0] [0] [0] [0] half(s(0())) = [0] >= [0] = 0() [0] [0] [1 0 0] [1 0 0] half(s(s(x))) = [0 1 0]x >= [0 1 0]x = s(half(x)) [0 0 0] [0 0 0] [1] [0] s(log(0())) = [0] >= [0] = s(0()) [0] [0] [1 0 0] [1] [1 0 0] [1] log(s(x)) = [0 1 0]x + [0] >= [0 1 0]x + [0] = s(log(half(s(x)))) [0 1 0] [1] [0 0 0] [0] problem: half(0()) -> 0() half(s(0())) -> 0() half(s(s(x))) -> s(half(x)) log(s(x)) -> s(log(half(s(x)))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [log](x0) = [0 0 0]x0 [0 0 0] , [1 1 0] [s](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [half](x0) = [0 1 1]x0 [0 1 1] , [0] [0] = [1] [0] orientation: [0] [0] half(0()) = [1] >= [1] = 0() [1] [0] [1] [0] half(s(0())) = [1] >= [1] = 0() [1] [0] [1 1 1] [1 1 1] half(s(s(x))) = [0 1 1]x >= [0 1 1]x = s(half(x)) [0 1 1] [0 1 1] [1 1 0] [1 1 0] log(s(x)) = [0 0 0]x >= [0 0 0]x = s(log(half(s(x)))) [0 0 0] [0 0 0] problem: half(0()) -> 0() half(s(s(x))) -> s(half(x)) log(s(x)) -> s(log(half(s(x)))) Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [0] [log](x0) = [1 0 1]x0 + [1] [1 1 0] [0], [1 0 0] [1] [s](x0) = [1 0 0]x0 + [1] [1 0 0] [0], [1 0 0] [half](x0) = [0 0 1]x0 [1 0 0] , [0] [0] = [0] [0] orientation: [0] [0] half(0()) = [0] >= [0] = 0() [0] [0] [1 0 0] [2] [1 0 0] [1] half(s(s(x))) = [1 0 0]x + [1] >= [1 0 0]x + [1] = s(half(x)) [1 0 0] [2] [1 0 0] [0] [2 0 0] [2] [2 0 0] [2] log(s(x)) = [2 0 0]x + [2] >= [2 0 0]x + [2] = s(log(half(s(x)))) [2 0 0] [2] [2 0 0] [1] problem: half(0()) -> 0() log(s(x)) -> s(log(half(s(x)))) Matrix Interpretation Processor: dim=3 interpretation: [1 1 0] [log](x0) = [0 1 0]x0 [0 0 0] , [1 0 0] [0] [s](x0) = [0 0 1]x0 + [1] [0 0 0] [0], [1 0 1] [0] [half](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [0] [0] = [0] [1] orientation: [1] [0] half(0()) = [0] >= [0] = 0() [1] [1] [1 0 1] [1] [1 0 0] [0] log(s(x)) = [0 0 1]x + [1] >= [0 0 0]x + [1] = s(log(half(s(x)))) [0 0 0] [0] [0 0 0] [0] problem: Qed