/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 f(s(x1),x2,x3,x4,x5) -> f(x1,x2,x3,x4,x5)
 f(0(),s(x2),x3,x4,x5) -> f(x2,x2,x3,x4,x5)
 f(0(),0(),s(x3),x4,x5) -> f(x3,x3,x3,x4,x5)
 f(0(),0(),0(),s(x4),x5) -> f(x4,x4,x4,x4,x5)
 f(0(),0(),0(),0(),s(x5)) -> f(x5,x5,x5,x5,x5)
 f(0(),0(),0(),0(),0()) -> 0()

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [0] = 0,
   
   [f](x0, x1, x2, x3, x4) = x0 + x1 + x2 + 5x3 + 4x4,
   
   [s](x0) = 3x0 + 2
  orientation:
   f(s(x1),x2,x3,x4,x5) = 3x1 + x2 + x3 + 5x4 + 4x5 + 2 >= x1 + x2 + x3 + 5x4 + 4x5 = f(x1,x2,x3,x4,x5)
   
   f(0(),s(x2),x3,x4,x5) = 3x2 + x3 + 5x4 + 4x5 + 2 >= 2x2 + x3 + 5x4 + 4x5 = f(x2,x2,x3,x4,x5)
   
   f(0(),0(),s(x3),x4,x5) = 3x3 + 5x4 + 4x5 + 2 >= 3x3 + 5x4 + 4x5 = f(x3,x3,x3,x4,x5)
   
   f(0(),0(),0(),s(x4),x5) = 15x4 + 4x5 + 10 >= 8x4 + 4x5 = f(x4,x4,x4,x4,x5)
   
   f(0(),0(),0(),0(),s(x5)) = 12x5 + 8 >= 12x5 = f(x5,x5,x5,x5,x5)
   
   f(0(),0(),0(),0(),0()) = 0 >= 0 = 0()
  problem:
   f(0(),0(),0(),0(),0()) -> 0()
  Matrix Interpretation Processor: dim=3
   
   interpretation:
          [0]
    [0] = [1]
          [0],
    
                              [1 0 0]     [1 1 0]     [1 0 0]     [1 0 0]     [1 0 0]  
    [f](x0, x1, x2, x3, x4) = [0 0 0]x0 + [0 0 0]x1 + [0 0 0]x2 + [0 0 0]x3 + [0 1 0]x4
                              [0 0 0]     [0 0 0]     [0 0 0]     [0 0 0]     [0 0 0]  
   orientation:
                             [1]    [0]      
    f(0(),0(),0(),0(),0()) = [1] >= [1] = 0()
                             [0]    [0]      
   problem:
    
   Qed