/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: s(s(0())) -> f(s(0())) g(x) -> h(x,x) s(x) -> h(x,0()) s(x) -> h(0(),x) f(g(x)) -> g(g(f(x))) g(s(x)) -> s(s(g(x))) h(f(x),g(x)) -> f(s(x)) s(s(0())) -> k(0()) k(0()) -> 0() s(s(s(0()))) -> k(s(0())) k(s(0())) -> s(0()) s(s(s(s(s(s(s(s(0())))))))) -> k(s(s(0()))) k(s(s(0()))) -> s(s(s(s(s(s(0())))))) h(k(x),g(x)) -> k(s(x)) Proof: Polynomial Interpretation Processor: dimension: 1 interpretation: [k](x0) = -1x0 + 2x0x0 + 1, [h](x0, x1) = x0 + x1, [g](x0) = 5x0 + 4, [f](x0) = -1x0 + 2x0x0, [s](x0) = x0 + 1, [0] = 0 orientation: s(s(0())) = 2 >= 1 = f(s(0())) g(x) = 5x + 4 >= 2x = h(x,x) s(x) = x + 1 >= x = h(x,0()) s(x) = x + 1 >= x = h(0(),x) f(g(x)) = 75x + 50x*x + 28 >= -25x + 50x*x + 24 = g(g(f(x))) g(s(x)) = 5x + 9 >= 5x + 6 = s(s(g(x))) h(f(x),g(x)) = 4x + 2x*x + 4 >= 3x + 2x*x + 1 = f(s(x)) s(s(0())) = 2 >= 1 = k(0()) k(0()) = 1 >= 0 = 0() s(s(s(0()))) = 3 >= 2 = k(s(0())) k(s(0())) = 2 >= 1 = s(0()) s(s(s(s(s(s(s(s(0())))))))) = 8 >= 7 = k(s(s(0()))) k(s(s(0()))) = 7 >= 6 = s(s(s(s(s(s(0())))))) h(k(x),g(x)) = 4x + 2x*x + 5 >= 3x + 2x*x + 2 = k(s(x)) problem: Qed