/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES

Problem 1: 

(VAR x y z)
(RULES
div(div(x,y),z) -> div(x,times(y,z))
div(0,y) -> 0
div(x,y) -> quot(x,y,y)
plus(0,y) -> y
plus(s(x),y) -> s(plus(x,y))
plus(x,0) -> x
quot(0,s(y),z) -> 0
quot(s(x),s(y),z) -> quot(x,y,z)
quot(x,0,s(z)) -> s(div(x,s(z)))
times(0,y) -> 0
times(s(0),y) -> y
times(s(x),y) -> plus(y,times(x,y))
)

Problem 1: 

Dependency Pairs Processor:
-> Pairs:
 DIV(div(x,y),z) -> DIV(x,times(y,z))
 DIV(div(x,y),z) -> TIMES(y,z)
 DIV(x,y) -> QUOT(x,y,y)
 PLUS(s(x),y) -> PLUS(x,y)
 QUOT(s(x),s(y),z) -> QUOT(x,y,z)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
 TIMES(s(x),y) -> PLUS(y,times(x,y))
 TIMES(s(x),y) -> TIMES(x,y)
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))

Problem 1: 

SCC Processor:
-> Pairs:
 DIV(div(x,y),z) -> DIV(x,times(y,z))
 DIV(div(x,y),z) -> TIMES(y,z)
 DIV(x,y) -> QUOT(x,y,y)
 PLUS(s(x),y) -> PLUS(x,y)
 QUOT(s(x),s(y),z) -> QUOT(x,y,z)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
 TIMES(s(x),y) -> PLUS(y,times(x,y))
 TIMES(s(x),y) -> TIMES(x,y)
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Strongly Connected Components:
->->Cycle:
->->-> Pairs:
 PLUS(s(x),y) -> PLUS(x,y)
->->-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->->Cycle:
->->-> Pairs:
 TIMES(s(x),y) -> TIMES(x,y)
->->-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->->Cycle:
->->-> Pairs:
 DIV(div(x,y),z) -> DIV(x,times(y,z))
 DIV(x,y) -> QUOT(x,y,y)
 QUOT(s(x),s(y),z) -> QUOT(x,y,z)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
->->-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))


The problem is decomposed in 3 subproblems.

Problem 1.1: 

Subterm Processor:
-> Pairs:
 PLUS(s(x),y) -> PLUS(x,y)
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Projection:
 pi(PLUS) = 1

Problem 1.1: 

SCC Processor:
-> Pairs:
 Empty
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.

Problem 1.2: 

Subterm Processor:
-> Pairs:
 TIMES(s(x),y) -> TIMES(x,y)
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Projection:
 pi(TIMES) = 1

Problem 1.2: 

SCC Processor:
-> Pairs:
 Empty
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.

Problem 1.3: 

Subterm Processor:
-> Pairs:
 DIV(div(x,y),z) -> DIV(x,times(y,z))
 DIV(x,y) -> QUOT(x,y,y)
 QUOT(s(x),s(y),z) -> QUOT(x,y,z)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Projection:
 pi(DIV) = 1
 pi(QUOT) = 1

Problem 1.3: 

SCC Processor:
-> Pairs:
 DIV(x,y) -> QUOT(x,y,y)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Strongly Connected Components:
->->Cycle:
->->-> Pairs:
 DIV(x,y) -> QUOT(x,y,y)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
->->-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))

Problem 1.3: 

Reduction Pair Processor:
-> Pairs:
 DIV(x,y) -> QUOT(x,y,y)
 QUOT(x,0,s(z)) -> DIV(x,s(z))
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
-> Usable rules:
 Empty
->Interpretation type:
 Linear
->Coefficients:
 Natural Numbers
->Dimension:
 1
->Bound:
 2
->Interpretation:
 
[0] = 2
[s](X) = 0
[DIV](X1,X2) = 2.X2 + 1
[QUOT](X1,X2,X3) = X2 + X3

Problem 1.3: 

SCC Processor:
-> Pairs:
 QUOT(x,0,s(z)) -> DIV(x,s(z))
-> Rules:
 div(div(x,y),z) -> div(x,times(y,z))
 div(0,y) -> 0
 div(x,y) -> quot(x,y,y)
 plus(0,y) -> y
 plus(s(x),y) -> s(plus(x,y))
 plus(x,0) -> x
 quot(0,s(y),z) -> 0
 quot(s(x),s(y),z) -> quot(x,y,z)
 quot(x,0,s(z)) -> s(div(x,s(z)))
 times(0,y) -> 0
 times(s(0),y) -> y
 times(s(x),y) -> plus(y,times(x,y))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.