/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 f(0(),1(),x) -> f(s(x),x,x)
 f(x,y,s(z)) -> s(f(0(),1(),z))

Proof:
 DP Processor:
  DPs:
   f#(0(),1(),x) -> f#(s(x),x,x)
   f#(x,y,s(z)) -> f#(0(),1(),z)
  TRS:
   f(0(),1(),x) -> f(s(x),x,x)
   f(x,y,s(z)) -> s(f(0(),1(),z))
  Subterm Criterion Processor:
   simple projection:
    pi(f#) = 2
   problem:
    DPs:
     f#(0(),1(),x) -> f#(s(x),x,x)
    TRS:
     f(0(),1(),x) -> f(s(x),x,x)
     f(x,y,s(z)) -> s(f(0(),1(),z))
   EDG Processor:
    DPs:
     f#(0(),1(),x) -> f#(s(x),x,x)
    TRS:
     f(0(),1(),x) -> f(s(x),x,x)
     f(x,y,s(z)) -> s(f(0(),1(),z))
    graph:
     
    SCC Processor:
     #sccs: 0
     #rules: 0
     #arcs: 0/1