/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR l l1 l2 x) (RULES append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l ) Problem 1: Innermost Equivalent Processor: -> Rules: append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: APPEND(l1,l2) -> IFAPPEND(l1,l2,l1) IFAPPEND(l1,l2,cons(x,l)) -> APPEND(l,l2) -> Rules: append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l Problem 1: SCC Processor: -> Pairs: APPEND(l1,l2) -> IFAPPEND(l1,l2,l1) IFAPPEND(l1,l2,cons(x,l)) -> APPEND(l,l2) -> Rules: append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: APPEND(l1,l2) -> IFAPPEND(l1,l2,l1) IFAPPEND(l1,l2,cons(x,l)) -> APPEND(l,l2) ->->-> Rules: append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l Problem 1: Subterm Processor: -> Pairs: APPEND(l1,l2) -> IFAPPEND(l1,l2,l1) IFAPPEND(l1,l2,cons(x,l)) -> APPEND(l,l2) -> Rules: append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l ->Projection: pi(APPEND) = 1 pi(IFAPPEND) = 3 Problem 1: SCC Processor: -> Pairs: APPEND(l1,l2) -> IFAPPEND(l1,l2,l1) -> Rules: append(l1,l2) -> ifappend(l1,l2,l1) hd(cons(x,l)) -> x ifappend(l1,l2,cons(x,l)) -> cons(x,append(l,l2)) ifappend(l1,l2,nil) -> l2 is_empty(cons(x,l)) -> false is_empty(nil) -> true tl(cons(x,l)) -> l ->Strongly Connected Components: There is no strongly connected component The problem is finite.