/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x) (RULES f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) ) Problem 1: Innermost Equivalent Processor: -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: F(a,f(x,a)) -> F(f(a,a),f(a,x)) F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) F(a,f(x,a)) -> F(a,x) -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) Problem 1: SCC Processor: -> Pairs: F(a,f(x,a)) -> F(f(a,a),f(a,x)) F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) F(a,f(x,a)) -> F(a,x) -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) F(a,f(x,a)) -> F(a,x) ->->-> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) Problem 1: Reduction Pairs Processor: -> Pairs: F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) F(a,f(x,a)) -> F(a,x) -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) -> Usable rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 2 ->Bound: 1 ->Interpretation: [f](X1,X2) = [1 0;0 0].X1 + [0 1;0 0].X2 [a] = [0;1] [F](X1,X2) = [1 0;1 0].X2 Problem 1: SCC Processor: -> Pairs: F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) ->->-> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) Problem 1: Reduction Pairs Processor: -> Pairs: F(a,f(x,a)) -> F(a,f(f(a,a),f(a,x))) -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) -> Usable rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) ->Interpretation type: Linear ->Coefficients: All rationals ->Dimension: 1 ->Bound: 4 ->Interpretation: [f](X1,X2) = 1/3.X1 + 1/2.X2 [a] = 2 [F](X1,X2) = 3.X2 Problem 1: SCC Processor: -> Pairs: Empty -> Rules: f(a,f(x,a)) -> f(a,f(f(a,a),f(a,x))) ->Strongly Connected Components: There is no strongly connected component The problem is finite.