/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y z) (RULES plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ) Problem 1: Dependency Pairs Processor: -> Pairs: PLUS(x,s(y)) -> PLUS(x,y) TIMES(x,plus(y,s(z))) -> PLUS(times(x,plus(y,times(s(z),0))),times(x,s(z))) TIMES(x,plus(y,s(z))) -> PLUS(y,times(s(z),0)) TIMES(x,plus(y,s(z))) -> TIMES(s(z),0) TIMES(x,plus(y,s(z))) -> TIMES(x,plus(y,times(s(z),0))) TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> PLUS(times(x,y),x) TIMES(x,s(y)) -> TIMES(x,y) -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) Problem 1: SCC Processor: -> Pairs: PLUS(x,s(y)) -> PLUS(x,y) TIMES(x,plus(y,s(z))) -> PLUS(times(x,plus(y,times(s(z),0))),times(x,s(z))) TIMES(x,plus(y,s(z))) -> PLUS(y,times(s(z),0)) TIMES(x,plus(y,s(z))) -> TIMES(s(z),0) TIMES(x,plus(y,s(z))) -> TIMES(x,plus(y,times(s(z),0))) TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> PLUS(times(x,y),x) TIMES(x,s(y)) -> TIMES(x,y) -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: PLUS(x,s(y)) -> PLUS(x,y) ->->-> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->->Cycle: ->->-> Pairs: TIMES(x,plus(y,s(z))) -> TIMES(x,plus(y,times(s(z),0))) TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> TIMES(x,y) ->->-> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) The problem is decomposed in 2 subproblems. Problem 1.1: Subterm Processor: -> Pairs: PLUS(x,s(y)) -> PLUS(x,y) -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Projection: pi(PLUS) = 2 Problem 1.1: SCC Processor: -> Pairs: Empty -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: Reduction Pair Processor: -> Pairs: TIMES(x,plus(y,s(z))) -> TIMES(x,plus(y,times(s(z),0))) TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> TIMES(x,y) -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) -> Usable rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Interpretation type: Simple mixed ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [plus](X1,X2) = X1 + X2 [times](X1,X2) = 2.X1.X2 [0] = 0 [s](X) = X + 2 [TIMES](X1,X2) = 2.X2 Problem 1.2: SCC Processor: -> Pairs: TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> TIMES(x,y) -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> TIMES(x,y) ->->-> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) Problem 1.2: Subterm Processor: -> Pairs: TIMES(x,plus(y,s(z))) -> TIMES(x,s(z)) TIMES(x,s(y)) -> TIMES(x,y) -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Projection: pi(TIMES) = 2 Problem 1.2: SCC Processor: -> Pairs: Empty -> Rules: plus(x,0) -> x plus(x,s(y)) -> s(plus(x,y)) times(x,plus(y,s(z))) -> plus(times(x,plus(y,times(s(z),0))),times(x,s(z))) times(x,0) -> 0 times(x,s(y)) -> plus(times(x,y),x) ->Strongly Connected Components: There is no strongly connected component The problem is finite.