/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (RULES f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) ) Problem 1: Innermost Equivalent Processor: -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: F(x,f(y,a)) -> F(f(f(f(a,x),y),a),h(a)) F(x,f(y,a)) -> F(f(f(a,x),y),a) F(x,f(y,a)) -> F(f(a,x),y) F(x,f(y,a)) -> F(a,x) -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) Problem 1: SCC Processor: -> Pairs: F(x,f(y,a)) -> F(f(f(f(a,x),y),a),h(a)) F(x,f(y,a)) -> F(f(f(a,x),y),a) F(x,f(y,a)) -> F(f(a,x),y) F(x,f(y,a)) -> F(a,x) -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(x,f(y,a)) -> F(f(a,x),y) F(x,f(y,a)) -> F(a,x) ->->-> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) Problem 1: Reduction Pairs Processor: -> Pairs: F(x,f(y,a)) -> F(f(a,x),y) F(x,f(y,a)) -> F(a,x) -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) -> Usable rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) ->Interpretation type: Simple mixed ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = 2.X1.X2 + 2 [a] = 1 [h](X) = 0 [F](X1,X2) = X1.X2 + X1 + 2.X2 Problem 1: SCC Processor: -> Pairs: F(x,f(y,a)) -> F(a,x) -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(x,f(y,a)) -> F(a,x) ->->-> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) Problem 1: Reduction Pairs Processor: -> Pairs: F(x,f(y,a)) -> F(a,x) -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [f](X1,X2) = 2 [a] = 0 [F](X1,X2) = 2.X1 + X2 Problem 1: SCC Processor: -> Pairs: Empty -> Rules: f(x,f(y,a)) -> f(f(f(f(a,x),y),a),h(a)) ->Strongly Connected Components: There is no strongly connected component The problem is finite.