/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 62 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 12 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: app(nil, y) -> y app(add(n, x), y) -> add(n, app(x, y)) reverse(nil) -> nil reverse(add(n, x)) -> app(reverse(x), add(n, nil)) shuffle(nil) -> nil shuffle(add(n, x)) -> add(n, shuffle(reverse(x))) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(add(x_1, x_2)) = 2 + 2*x_1 + x_2 POL(app(x_1, x_2)) = x_1 + x_2 POL(nil) = 0 POL(reverse(x_1)) = x_1 POL(shuffle(x_1)) = 2 + 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: shuffle(nil) -> nil shuffle(add(n, x)) -> add(n, shuffle(reverse(x))) ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: app(nil, y) -> y app(add(n, x), y) -> add(n, app(x, y)) reverse(nil) -> nil reverse(add(n, x)) -> app(reverse(x), add(n, nil)) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(add(x_1, x_2)) = 2*x_1 + x_2 POL(app(x_1, x_2)) = x_1 + x_2 POL(nil) = 0 POL(reverse(x_1)) = 2 + x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: reverse(nil) -> nil ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: app(nil, y) -> y app(add(n, x), y) -> add(n, app(x, y)) reverse(add(n, x)) -> app(reverse(x), add(n, nil)) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: reverse_1 > app_2 > add_2 reverse_1 > nil > add_2 Status: app_2: multiset status nil: multiset status add_2: multiset status reverse_1: [1] With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: app(nil, y) -> y app(add(n, x), y) -> add(n, app(x, y)) reverse(add(n, x)) -> app(reverse(x), add(n, nil)) ---------------------------------------- (6) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (7) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (8) YES