/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES
proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Termination w.r.t. Q of the given QTRS could be proven:

(0) QTRS
(1) Overlay + Local Confluence [EQUIVALENT, 0 ms]
(2) QTRS
(3) DependencyPairsProof [EQUIVALENT, 0 ms]
(4) QDP
(5) TransformationProof [EQUIVALENT, 0 ms]
(6) QDP
(7) DependencyGraphProof [EQUIVALENT, 0 ms]
(8) QDP
(9) UsableRulesProof [EQUIVALENT, 0 ms]
(10) QDP
(11) TransformationProof [EQUIVALENT, 0 ms]
(12) QDP
(13) DependencyGraphProof [EQUIVALENT, 0 ms]
(14) TRUE


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   f(x, f(a, f(f(a, a), a))) -> f(f(a, x), x)

Q is empty.

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(1) Overlay + Local Confluence (EQUIVALENT)
The TRS is overlay and locally confluent. By [NOC] we can switch to innermost.
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(2)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   f(x, f(a, f(f(a, a), a))) -> f(f(a, x), x)

The set Q consists of the following terms:

   f(x0, f(a, f(f(a, a), a)))


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(3) DependencyPairsProof (EQUIVALENT)
Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
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(4)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   F(x, f(a, f(f(a, a), a))) -> F(f(a, x), x)
   F(x, f(a, f(f(a, a), a))) -> F(a, x)

The TRS R consists of the following rules:

   f(x, f(a, f(f(a, a), a))) -> f(f(a, x), x)

The set Q consists of the following terms:

   f(x0, f(a, f(f(a, a), a)))

We have to consider all minimal (P,Q,R)-chains.
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(5) TransformationProof (EQUIVALENT)
By narrowing [LPAR04] the rule F(x, f(a, f(f(a, a), a))) -> F(f(a, x), x) at position [] we obtained the following new rules [LPAR04]:

   (F(f(a, f(f(a, a), a)), f(a, f(f(a, a), a))) -> F(f(f(a, a), a), f(a, f(f(a, a), a))),F(f(a, f(f(a, a), a)), f(a, f(f(a, a), a))) -> F(f(f(a, a), a), f(a, f(f(a, a), a))))


----------------------------------------

(6)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   F(x, f(a, f(f(a, a), a))) -> F(a, x)
   F(f(a, f(f(a, a), a)), f(a, f(f(a, a), a))) -> F(f(f(a, a), a), f(a, f(f(a, a), a)))

The TRS R consists of the following rules:

   f(x, f(a, f(f(a, a), a))) -> f(f(a, x), x)

The set Q consists of the following terms:

   f(x0, f(a, f(f(a, a), a)))

We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(7) DependencyGraphProof (EQUIVALENT)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node.
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(8)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   F(x, f(a, f(f(a, a), a))) -> F(a, x)

The TRS R consists of the following rules:

   f(x, f(a, f(f(a, a), a))) -> f(f(a, x), x)

The set Q consists of the following terms:

   f(x0, f(a, f(f(a, a), a)))

We have to consider all minimal (P,Q,R)-chains.
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(9) UsableRulesProof (EQUIVALENT)
As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R.
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(10)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   F(x, f(a, f(f(a, a), a))) -> F(a, x)

R is empty.
The set Q consists of the following terms:

   f(x0, f(a, f(f(a, a), a)))

We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(11) TransformationProof (EQUIVALENT)
By instantiating [LPAR04] the rule F(x, f(a, f(f(a, a), a))) -> F(a, x) we obtained the following new rules [LPAR04]:

   (F(a, f(a, f(f(a, a), a))) -> F(a, a),F(a, f(a, f(f(a, a), a))) -> F(a, a))


----------------------------------------

(12)
Obligation:
Q DP problem:
The TRS P consists of the following rules:

   F(a, f(a, f(f(a, a), a))) -> F(a, a)

R is empty.
The set Q consists of the following terms:

   f(x0, f(a, f(f(a, a), a)))

We have to consider all minimal (P,Q,R)-chains.
----------------------------------------

(13) DependencyGraphProof (EQUIVALENT)
The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node.
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(14)
TRUE