/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 100 ms] (2) QTRS (3) RisEmptyProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: fib(0) -> 0 fib(s(0)) -> s(0) fib(s(s(0))) -> s(0) fib(s(s(x))) -> sp(g(x)) g(0) -> pair(s(0), 0) g(s(0)) -> pair(s(0), s(0)) g(s(x)) -> np(g(x)) sp(pair(x, y)) -> +(x, y) np(pair(x, y)) -> pair(+(x, y), x) +(x, 0) -> x +(x, s(y)) -> s(+(x, y)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: [fib_1, g_1] > [sp_1, np_1, +_2] > s_1 > [0, pair_2] Status: fib_1: multiset status 0: multiset status s_1: multiset status sp_1: multiset status g_1: multiset status pair_2: multiset status np_1: multiset status +_2: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: fib(0) -> 0 fib(s(0)) -> s(0) fib(s(s(0))) -> s(0) fib(s(s(x))) -> sp(g(x)) g(0) -> pair(s(0), 0) g(s(0)) -> pair(s(0), s(0)) g(s(x)) -> np(g(x)) sp(pair(x, y)) -> +(x, y) np(pair(x, y)) -> pair(+(x, y), x) +(x, 0) -> x +(x, s(y)) -> s(+(x, y)) ---------------------------------------- (2) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (3) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (4) YES