/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: c(c(c(b(x)))) -> a(1(),b(c(x))) b(c(b(c(x)))) -> a(0(),a(1(),x)) a(0(),x) -> c(c(x)) a(1(),x) -> c(b(x)) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1] [0] = [0], [3 0] [2 1] [1] [a](x0, x1) = [1 0]x0 + [1 1]x1 + [1], [0] [1] = [0], [1 1] [1] [c](x0) = [1 0]x0 + [1], [1 1] [b](x0) = [1 0]x0 orientation: [5 3] [6] [5 3] [6] c(c(c(b(x)))) = [3 2]x + [4] >= [3 2]x + [4] = a(1(),b(c(x))) [5 3] [7] [5 3] [7] b(c(b(c(x)))) = [3 2]x + [4] >= [3 2]x + [4] = a(0(),a(1(),x)) [2 1] [4] [2 1] [3] a(0(),x) = [1 1]x + [2] >= [1 1]x + [2] = c(c(x)) [2 1] [1] [2 1] [1] a(1(),x) = [1 1]x + [1] >= [1 1]x + [1] = c(b(x)) problem: c(c(c(b(x)))) -> a(1(),b(c(x))) b(c(b(c(x)))) -> a(0(),a(1(),x)) a(1(),x) -> c(b(x)) Matrix Interpretation Processor: dim=3 interpretation: [0] [0] = [0] [0], [1 0 0] [1 0 1] [a](x0, x1) = [0 0 1]x0 + [0 0 0]x1 [0 0 0] [0 1 0] , [0] [1] = [0] [1], [1 0 1] [0] [c](x0) = [0 0 0]x0 + [1] [0 1 0] [0], [b](x0) = x0 orientation: [1 1 1] [1] [1 1 1] [0] c(c(c(b(x)))) = [0 0 0]x + [1] >= [0 0 0]x + [1] = a(1(),b(c(x))) [0 0 0] [1] [0 0 0] [1] [1 1 1] [0] [1 1 1] [0] b(c(b(c(x)))) = [0 0 0]x + [1] >= [0 0 0]x + [0] = a(0(),a(1(),x)) [0 0 0] [1] [0 0 0] [1] [1 0 1] [0] [1 0 1] [0] a(1(),x) = [0 0 0]x + [1] >= [0 0 0]x + [1] = c(b(x)) [0 1 0] [0] [0 1 0] [0] problem: b(c(b(c(x)))) -> a(0(),a(1(),x)) a(1(),x) -> c(b(x)) Matrix Interpretation Processor: dim=3 interpretation: [0] [0] = [0] [0], [1 0 0] [1 0 1] [a](x0, x1) = [0 1 0]x0 + [1 0 0]x1 [0 0 0] [0 1 0] , [0] [1] = [1] [0], [0] [c](x0) = x0 + [1] [0], [1 0 1] [b](x0) = [1 0 0]x0 [0 1 0] orientation: [1 1 1] [1] [1 1 1] [0] b(c(b(c(x)))) = [1 0 1]x + [0] >= [1 0 1]x + [0] = a(0(),a(1(),x)) [1 0 0] [1] [1 0 0] [1] [1 0 1] [0] [1 0 1] [0] a(1(),x) = [1 0 0]x + [1] >= [1 0 0]x + [1] = c(b(x)) [0 1 0] [0] [0 1 0] [0] problem: a(1(),x) -> c(b(x)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [1 1 0] [a](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [0] [1] = [0] [1], [1 0 1] [c](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [b](x0) = [0 0 0]x0 [0 1 0] orientation: [1 1 0] [1] [1 1 0] a(1(),x) = [0 0 0]x + [0] >= [0 0 0]x = c(b(x)) [0 0 0] [0] [0 0 0] problem: Qed