/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: f(f(x)) -> f(c(f(x))) f(f(x)) -> f(d(f(x))) g(c(x)) -> x g(d(x)) -> x g(c(h(0()))) -> g(d(1())) g(c(1())) -> g(d(h(0()))) g(h(x)) -> g(x) Proof: Matrix Interpretation Processor: dim=3 interpretation: [0] [1] = [1] [0], [1 0 0] [h](x0) = [1 1 0]x0 [0 0 1] , [0] [0] = [0] [1], [1 0 1] [g](x0) = [0 1 1]x0 [1 0 1] , [1 0 1] [d](x0) = [0 0 0]x0 [0 1 0] , [1 0 0] [c](x0) = [0 0 0]x0 [0 1 1] , [1 1 0] [0] [f](x0) = [0 0 0]x0 + [1] [0 0 0] [0] orientation: [1 1 0] [1] [1 1 0] [0] f(f(x)) = [0 0 0]x + [1] >= [0 0 0]x + [1] = f(c(f(x))) [0 0 0] [0] [0 0 0] [0] [1 1 0] [1] [1 1 0] [0] f(f(x)) = [0 0 0]x + [1] >= [0 0 0]x + [1] = f(d(f(x))) [0 0 0] [0] [0 0 0] [0] [1 1 1] g(c(x)) = [0 1 1]x >= x = x [1 1 1] [1 1 1] g(d(x)) = [0 1 0]x >= x = x [1 1 1] [1] [1] g(c(h(0()))) = [1] >= [1] = g(d(1())) [1] [1] [1] [1] g(c(1())) = [1] >= [0] = g(d(h(0()))) [1] [1] [1 0 1] [1 0 1] g(h(x)) = [1 1 1]x >= [0 1 1]x = g(x) [1 0 1] [1 0 1] problem: g(c(x)) -> x g(d(x)) -> x g(c(h(0()))) -> g(d(1())) g(c(1())) -> g(d(h(0()))) g(h(x)) -> g(x) Matrix Interpretation Processor: dim=3 interpretation: [0] [1] = [1] [0], [0] [h](x0) = x0 + [1] [0], [0] [0] = [0] [0], [1 1 0] [g](x0) = [0 0 1]x0 [0 1 0] , [1 0 0] [d](x0) = [0 0 1]x0 [0 1 0] , [1 1 0] [c](x0) = [0 0 1]x0 [0 1 0] orientation: [1 1 1] g(c(x)) = [0 1 0]x >= x = x [0 0 1] [1 0 1] g(d(x)) = [0 1 0]x >= x = x [0 0 1] [1] [0] g(c(h(0()))) = [1] >= [1] = g(d(1())) [0] [0] [1] [0] g(c(1())) = [1] >= [1] = g(d(h(0()))) [0] [0] [1 1 0] [1] [1 1 0] g(h(x)) = [0 0 1]x + [0] >= [0 0 1]x = g(x) [0 1 0] [1] [0 1 0] problem: g(c(x)) -> x g(d(x)) -> x Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1] [g](x0) = [0 0 1]x0 + [0] [0 0 1] [1], [1 0 0] [d](x0) = [0 0 0]x0 [0 1 1] , [1 0 0] [c](x0) = [0 0 0]x0 [0 1 1] orientation: [1 0 0] [1] g(c(x)) = [0 1 1]x + [0] >= x = x [0 1 1] [1] [1 0 0] [1] g(d(x)) = [0 1 1]x + [0] >= x = x [0 1 1] [1] problem: Qed