/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(f(),a(g(),a(f(),x))) -> a(f(),a(g(),a(g(),a(f(),x)))) a(g(),a(f(),a(g(),x))) -> a(g(),a(f(),a(f(),a(g(),x)))) Proof: Extended Uncurrying Processor: application symbol: a symbol table: g ==> g0/0 g1/1 f ==> f0/0 f1/1 uncurry-rules: a(f0(),x1) -> f1(x1) a(g0(),x3) -> g1(x3) eta-rules: problem: f1(g1(f1(x))) -> f1(g1(g1(f1(x)))) g1(f1(g1(x))) -> g1(f1(f1(g1(x)))) a(f0(),x1) -> f1(x1) a(g0(),x3) -> g1(x3) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [g1](x0) = [0 0 0]x0 [0 1 0] , [0] [g0] = [0] [0], [1 0 1] [0] [f1](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [0] [f0] = [0] [1], [1 0 0] [1 0 1] [a](x0, x1) = [0 0 1]x0 + [0 1 0]x1 [0 0 0] [0 1 0] orientation: [1 0 1] [1] [1 0 1] [0] f1(g1(f1(x))) = [0 0 0]x + [1] >= [0 0 0]x + [1] = f1(g1(g1(f1(x)))) [0 0 0] [0] [0 0 0] [0] [1 1 0] [0] [1 1 0] [0] g1(f1(g1(x))) = [0 0 0]x + [0] >= [0 0 0]x + [0] = g1(f1(f1(g1(x)))) [0 0 0] [1] [0 0 0] [1] [1 0 1] [0] [1 0 1] [0] a(f0(),x1) = [0 1 0]x1 + [1] >= [0 0 0]x1 + [1] = f1(x1) [0 1 0] [0] [0 0 0] [0] [1 0 1] [1 0 0] a(g0(),x3) = [0 1 0]x3 >= [0 0 0]x3 = g1(x3) [0 1 0] [0 1 0] problem: g1(f1(g1(x))) -> g1(f1(f1(g1(x)))) a(f0(),x1) -> f1(x1) a(g0(),x3) -> g1(x3) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [0] [g1](x0) = [0 0 0]x0 + [1] [1 0 0] [0], [0] [g0] = [0] [0], [1 0 0] [f1](x0) = [0 0 0]x0 [0 1 0] , [0] [f0] = [0] [0], [1 0 0] [1 0 1] [0] [a](x0, x1) = [0 0 0]x0 + [0 1 0]x1 + [1] [0 0 0] [1 1 1] [0] orientation: [1 0 1] [1] [1 0 1] [0] g1(f1(g1(x))) = [0 0 0]x + [1] >= [0 0 0]x + [1] = g1(f1(f1(g1(x)))) [1 0 1] [0] [1 0 1] [0] [1 0 1] [0] [1 0 0] a(f0(),x1) = [0 1 0]x1 + [1] >= [0 0 0]x1 = f1(x1) [1 1 1] [0] [0 1 0] [1 0 1] [0] [1 0 1] [0] a(g0(),x3) = [0 1 0]x3 + [1] >= [0 0 0]x3 + [1] = g1(x3) [1 1 1] [0] [1 0 0] [0] problem: a(f0(),x1) -> f1(x1) a(g0(),x3) -> g1(x3) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [g1](x0) = [0 0 0]x0 [0 0 0] , [0] [g0] = [0] [0], [1 0 0] [f1](x0) = [0 0 0]x0 [0 0 0] , [0] [f0] = [0] [0], [1 0 0] [1 0 0] [1] [a](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [0] orientation: [1 0 0] [1] [1 0 0] a(f0(),x1) = [0 0 0]x1 + [0] >= [0 0 0]x1 = f1(x1) [0 0 0] [0] [0 0 0] [1 0 0] [1] [1 0 0] a(g0(),x3) = [0 0 0]x3 + [0] >= [0 0 0]x3 = g1(x3) [0 0 0] [0] [0 0 0] problem: Qed