/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 52 ms] (2) QTRS (3) QTRSRRRProof [EQUIVALENT, 10 ms] (4) QTRS (5) QTRSRRRProof [EQUIVALENT, 0 ms] (6) QTRS (7) RisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: flatten(nil) -> nil flatten(unit(x)) -> flatten(x) flatten(++(x, y)) -> ++(flatten(x), flatten(y)) flatten(++(unit(x), y)) -> ++(flatten(x), flatten(y)) flatten(flatten(x)) -> flatten(x) rev(nil) -> nil rev(unit(x)) -> unit(x) rev(++(x, y)) -> ++(rev(y), rev(x)) rev(rev(x)) -> x ++(x, nil) -> x ++(nil, y) -> y ++(++(x, y), z) -> ++(x, ++(y, z)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(++(x_1, x_2)) = x_1 + x_2 POL(flatten(x_1)) = x_1 POL(nil) = 2 POL(rev(x_1)) = 2*x_1 POL(unit(x_1)) = 1 + 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: flatten(unit(x)) -> flatten(x) flatten(++(unit(x), y)) -> ++(flatten(x), flatten(y)) rev(nil) -> nil rev(unit(x)) -> unit(x) ++(x, nil) -> x ++(nil, y) -> y ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: flatten(nil) -> nil flatten(++(x, y)) -> ++(flatten(x), flatten(y)) flatten(flatten(x)) -> flatten(x) rev(++(x, y)) -> ++(rev(y), rev(x)) rev(rev(x)) -> x ++(++(x, y), z) -> ++(x, ++(y, z)) Q is empty. ---------------------------------------- (3) QTRSRRRProof (EQUIVALENT) Used ordering: Polynomial interpretation [POLO]: POL(++(x_1, x_2)) = 1 + x_1 + x_2 POL(flatten(x_1)) = 2*x_1 POL(nil) = 2 POL(rev(x_1)) = 2*x_1 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: flatten(nil) -> nil flatten(++(x, y)) -> ++(flatten(x), flatten(y)) rev(++(x, y)) -> ++(rev(y), rev(x)) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: flatten(flatten(x)) -> flatten(x) rev(rev(x)) -> x ++(++(x, y), z) -> ++(x, ++(y, z)) Q is empty. ---------------------------------------- (5) QTRSRRRProof (EQUIVALENT) Used ordering: Knuth-Bendix order [KBO] with precedence:flatten_1 > ++_2 > rev_1 and weight map: flatten_1=0 rev_1=1 ++_2=0 The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: flatten(flatten(x)) -> flatten(x) rev(rev(x)) -> x ++(++(x, y), z) -> ++(x, ++(y, z)) ---------------------------------------- (6) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (7) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (8) YES