/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (RULES plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x ) Problem 1: Innermost Equivalent Processor: -> Rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: TIMES(x,plus(y,1)) -> PLUS(times(x,plus(y,times(1,0))),x) TIMES(x,plus(y,1)) -> PLUS(y,times(1,0)) TIMES(x,plus(y,1)) -> TIMES(1,0) TIMES(x,plus(y,1)) -> TIMES(x,plus(y,times(1,0))) -> Rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x Problem 1: SCC Processor: -> Pairs: TIMES(x,plus(y,1)) -> PLUS(times(x,plus(y,times(1,0))),x) TIMES(x,plus(y,1)) -> PLUS(y,times(1,0)) TIMES(x,plus(y,1)) -> TIMES(1,0) TIMES(x,plus(y,1)) -> TIMES(x,plus(y,times(1,0))) -> Rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: TIMES(x,plus(y,1)) -> TIMES(x,plus(y,times(1,0))) ->->-> Rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x Problem 1: Reduction Pairs Processor: -> Pairs: TIMES(x,plus(y,1)) -> TIMES(x,plus(y,times(1,0))) -> Rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x -> Usable rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x ->Interpretation type: Simple mixed ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [plus](X1,X2) = X1 + 2.X2 [times](X1,X2) = 2.X1.X2 [0] = 0 [1] = 2 [TIMES](X1,X2) = 2.X2 Problem 1: SCC Processor: -> Pairs: Empty -> Rules: plus(x,0) -> x times(x,plus(y,1)) -> plus(times(x,plus(y,times(1,0))),x) times(x,0) -> 0 times(x,1) -> x ->Strongly Connected Components: There is no strongly connected component The problem is finite.