/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y z) (RULES f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ) Problem 1: Innermost Equivalent Processor: -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: F(.(.(x,y),z)) -> F(.(x,.(y,z))) F(.(nil,y)) -> F(y) G(.(x,.(y,z))) -> G(.(.(x,y),z)) G(.(x,nil)) -> G(x) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil Problem 1: SCC Processor: -> Pairs: F(.(.(x,y),z)) -> F(.(x,.(y,z))) F(.(nil,y)) -> F(y) G(.(x,.(y,z))) -> G(.(.(x,y),z)) G(.(x,nil)) -> G(x) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G(.(x,.(y,z))) -> G(.(.(x,y),z)) G(.(x,nil)) -> G(x) ->->-> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->->Cycle: ->->-> Pairs: F(.(.(x,y),z)) -> F(.(x,.(y,z))) F(.(nil,y)) -> F(y) ->->-> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil The problem is decomposed in 2 subproblems. Problem 1.1: Reduction Pairs Processor: -> Pairs: G(.(x,.(y,z))) -> G(.(.(x,y),z)) G(.(x,nil)) -> G(x) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [.](X1,X2) = X1 + 2.X2 + 2 [nil] = 0 [G](X) = X Problem 1.1: SCC Processor: -> Pairs: G(.(x,nil)) -> G(x) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G(.(x,nil)) -> G(x) ->->-> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil Problem 1.1: Subterm Processor: -> Pairs: G(.(x,nil)) -> G(x) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Projection: pi(G) = 1 Problem 1.1: SCC Processor: -> Pairs: Empty -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: Reduction Pairs Processor: -> Pairs: F(.(.(x,y),z)) -> F(.(x,.(y,z))) F(.(nil,y)) -> F(y) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Natural Numbers ->Dimension: 1 ->Bound: 2 ->Interpretation: [.](X1,X2) = 2.X1 + X2 + 2 [nil] = 0 [F](X) = 2.X Problem 1.2: SCC Processor: -> Pairs: F(.(nil,y)) -> F(y) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: F(.(nil,y)) -> F(y) ->->-> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil Problem 1.2: Subterm Processor: -> Pairs: F(.(nil,y)) -> F(y) -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Projection: pi(F) = 1 Problem 1.2: SCC Processor: -> Pairs: Empty -> Rules: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil,y)) -> .(nil,f(y)) f(nil) -> nil g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil)) -> .(g(x),nil) g(nil) -> nil ->Strongly Connected Components: There is no strongly connected component The problem is finite.