/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: and(tt(),X) -> activate(X) plus(N,0()) -> N plus(N,s(M)) -> s(plus(N,M)) activate(X) -> X Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [0] [s](x0) = [0 0 1]x0 + [1] [0 1 0] [0], [1 0 0] [1 1 1] [0] [plus](x0, x1) = [0 1 1]x0 + [0 0 1]x1 + [1] [0 1 1] [0 1 0] [0], [0] [0] = [1] [0], [activate](x0) = x0 , [1 0 0] [1] [and](x0, x1) = [0 0 0]x0 + x1 + [0] [0 0 0] [0], [0] [tt] = [0] [0] orientation: [1] and(tt(),X) = X + [0] >= X = activate(X) [0] [1 0 0] [1] plus(N,0()) = [0 1 1]N + [1] >= N = N [0 1 1] [1] [1 1 1] [1 0 0] [1] [1 1 1] [1 0 0] [0] plus(N,s(M)) = [0 1 0]M + [0 1 1]N + [1] >= [0 1 0]M + [0 1 1]N + [1] = s(plus(N,M)) [0 0 1] [0 1 1] [1] [0 0 1] [0 1 1] [1] activate(X) = X >= X = X problem: activate(X) -> X Matrix Interpretation Processor: dim=3 interpretation: [1] [activate](x0) = x0 + [0] [0] orientation: [1] activate(X) = X + [0] >= X = X [0] problem: Qed