/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: d(x) -> e(u(x)) d(u(x)) -> c(x) c(u(x)) -> b(x) v(e(x)) -> x b(u(x)) -> a(e(x)) Proof: String Reversal Processor: d(x) -> u(e(x)) u(d(x)) -> c(x) u(c(x)) -> b(x) e(v(x)) -> x u(b(x)) -> e(a(x)) KBO Processor: weight function: w0 = 1 w(a) = w(v) = w(b) = w(c) = w(u) = w(d) = 1 w(e) = 0 precedence: e > d > a ~ v ~ b ~ c ~ u problem: Qed