/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- NO Problem: f(n__b(),X,n__c()) -> f(X,c(),X) c() -> b() b() -> n__b() c() -> n__c() activate(n__b()) -> b() activate(n__c()) -> c() activate(X) -> X Proof: Matrix Interpretation Processor: dim=1 interpretation: [activate](x0) = x0 + 5, [b] = 3, [c] = 3, [f](x0, x1, x2) = x0 + 6x1 + 5x2 + 1, [n__c] = 3, [n__b] = 3 orientation: f(n__b(),X,n__c()) = 6X + 19 >= 6X + 19 = f(X,c(),X) c() = 3 >= 3 = b() b() = 3 >= 3 = n__b() c() = 3 >= 3 = n__c() activate(n__b()) = 8 >= 3 = b() activate(n__c()) = 8 >= 3 = c() activate(X) = X + 5 >= X = X problem: f(n__b(),X,n__c()) -> f(X,c(),X) c() -> b() b() -> n__b() c() -> n__c() Unfolding Processor: loop length: 4 terms: f(c(),c(),c()) f(c(),c(),n__c()) f(b(),c(),n__c()) f(n__b(),c(),n__c()) context: [] substitution: Qed