/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES
proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Termination w.r.t. Q of the given QTRS could be proven:

(0) QTRS
(1) QTRSRRRProof [EQUIVALENT, 37 ms]
(2) QTRS
(3) RisEmptyProof [EQUIVALENT, 0 ms]
(4) YES


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   a____(__(X, Y), Z) -> a____(mark(X), a____(mark(Y), mark(Z)))
   a____(X, nil) -> mark(X)
   a____(nil, X) -> mark(X)
   a__and(tt, X) -> mark(X)
   a__isNePal(__(I, __(P, I))) -> tt
   mark(__(X1, X2)) -> a____(mark(X1), mark(X2))
   mark(and(X1, X2)) -> a__and(mark(X1), X2)
   mark(isNePal(X)) -> a__isNePal(mark(X))
   mark(nil) -> nil
   mark(tt) -> tt
   a____(X1, X2) -> __(X1, X2)
   a__and(X1, X2) -> and(X1, X2)
   a__isNePal(X) -> isNePal(X)

Q is empty.

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(1) QTRSRRRProof (EQUIVALENT)
Used ordering:
Knuth-Bendix order [KBO] with precedence:mark_1 > a__isNePal_1 > tt > a__and_2 > nil > a_____2 > isNePal_1 > and_2 > ___2

and weight map:

   nil=1
   tt=4
   mark_1=0
   a__isNePal_1=1
   isNePal_1=1
   ___2=0
   a_____2=0
   a__and_2=0
   and_2=0

The variable weight is 1With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly:

   a____(__(X, Y), Z) -> a____(mark(X), a____(mark(Y), mark(Z)))
   a____(X, nil) -> mark(X)
   a____(nil, X) -> mark(X)
   a__and(tt, X) -> mark(X)
   a__isNePal(__(I, __(P, I))) -> tt
   mark(__(X1, X2)) -> a____(mark(X1), mark(X2))
   mark(and(X1, X2)) -> a__and(mark(X1), X2)
   mark(isNePal(X)) -> a__isNePal(mark(X))
   mark(nil) -> nil
   mark(tt) -> tt
   a____(X1, X2) -> __(X1, X2)
   a__and(X1, X2) -> and(X1, X2)
   a__isNePal(X) -> isNePal(X)




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(2)
Obligation:
Q restricted rewrite system:
R is empty.
Q is empty.

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(3) RisEmptyProof (EQUIVALENT)
The TRS R is empty. Hence, termination is trivially proven.
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(4)
YES