/export/starexec/sandbox/solver/bin/starexec_run_standard /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES
proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty


Termination w.r.t. Q of the given QTRS could be proven:

(0) QTRS
(1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms]
(2) YES


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(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   f(n__f(n__a)) -> f(n__g(f(n__a)))
   f(X) -> n__f(X)
   a -> n__a
   g(X) -> n__g(X)
   activate(n__f(X)) -> f(X)
   activate(n__a) -> a
   activate(n__g(X)) -> g(X)
   activate(X) -> X

Q is empty.

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(1) RFCMatchBoundsTRSProof (EQUIVALENT)
Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 2. This implies Q-termination of R.
The following rules were used to construct the certificate:

   f(n__f(n__a)) -> f(n__g(f(n__a)))
   f(X) -> n__f(X)
   a -> n__a
   g(X) -> n__g(X)
   activate(n__f(X)) -> f(X)
   activate(n__a) -> a
   activate(n__g(X)) -> g(X)
   activate(X) -> X

The certificate found is represented by the following graph.
The certificate consists of the following enumerated nodes:
1, 2, 3, 4, 5, 6, 7, 8

Node 1 is start node and node 2 is final node.

Those nodes are connected through the following edges:

* 1 to 3 labelled f_1(0), n__f_1(1)* 1 to 2 labelled n__f_1(0), n__a(0), n__g_1(0), f_1(0), a(0), g_1(0), activate_1(0), n__f_1(1), n__a(1), n__g_1(1), f_1(1), a(1), g_1(1), activate_1(1), n__f_1(2), n__a(2), n__g_1(2)* 1 to 6 labelled f_1(1), n__f_1(2)* 2 to 2 labelled #_1(0)* 3 to 4 labelled n__g_1(0)* 4 to 5 labelled f_1(0), n__f_1(1)* 5 to 2 labelled n__a(0)* 6 to 7 labelled n__g_1(1)* 7 to 8 labelled f_1(1), n__f_1(2)* 8 to 2 labelled n__a(1)


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(2)
YES