/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem 1: 

(VAR X X1 X2 Y Z)
(RULES
a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
a__2nd(X) -> 2nd(X)
a__from(X) -> cons(mark(X),from(s(X)))
a__from(X) -> from(X)
mark(2nd(X)) -> a__2nd(mark(X))
mark(cons(X1,X2)) -> cons(mark(X1),X2)
mark(from(X)) -> a__from(mark(X))
mark(s(X)) -> s(mark(X))
)

Problem 1: 

Dependency Pairs Processor:
-> Pairs:
 A__2ND(cons(X,cons(Y,Z))) -> MARK(Y)
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> A__2ND(mark(X))
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))

Problem 1: 

SCC Processor:
-> Pairs:
 A__2ND(cons(X,cons(Y,Z))) -> MARK(Y)
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> A__2ND(mark(X))
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Strongly Connected Components:
->->Cycle:
->->-> Pairs:
 A__2ND(cons(X,cons(Y,Z))) -> MARK(Y)
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> A__2ND(mark(X))
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
->->-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))

Problem 1: 

Reduction Pair Processor:
-> Pairs:
 A__2ND(cons(X,cons(Y,Z))) -> MARK(Y)
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> A__2ND(mark(X))
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
-> Usable rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Interpretation type:
 Linear
->Coefficients:
 All rationals
->Dimension:
 1
->Bound:
 2
->Interpretation:
 
[a__2nd](X) = 2.X + 1/2
[a__from](X) = 2.X + 2
[mark](X) = X
[2nd](X) = 2.X + 1/2
[cons](X1,X2) = X1 + 1/2.X2 + 1/2
[from](X) = 2.X + 2
[s](X) = X
[A__2ND](X) = 2.X + 1/2
[A__FROM](X) = X + 1
[MARK](X) = X

Problem 1: 

SCC Processor:
-> Pairs:
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> A__2ND(mark(X))
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Strongly Connected Components:
->->Cycle:
->->-> Pairs:
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
->->-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))

Problem 1: 

Reduction Pair Processor:
-> Pairs:
 A__FROM(X) -> MARK(X)
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
-> Usable rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Interpretation type:
 Linear
->Coefficients:
 All rationals
->Dimension:
 1
->Bound:
 2
->Interpretation:
 
[a__2nd](X) = 2.X + 1/2
[a__from](X) = 2.X + 1/2
[mark](X) = X
[2nd](X) = 2.X + 1/2
[cons](X1,X2) = X1 + 1/2.X2
[from](X) = 2.X + 1/2
[s](X) = X
[A__FROM](X) = 2.X + 1/2
[MARK](X) = X

Problem 1: 

SCC Processor:
-> Pairs:
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> A__FROM(mark(X))
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Strongly Connected Components:
->->Cycle:
->->-> Pairs:
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
->->-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))

Problem 1: 

Subterm Processor:
-> Pairs:
 MARK(2nd(X)) -> MARK(X)
 MARK(cons(X1,X2)) -> MARK(X1)
 MARK(from(X)) -> MARK(X)
 MARK(s(X)) -> MARK(X)
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Projection:
 pi(MARK) = 1

Problem 1: 

SCC Processor:
-> Pairs:
 Empty
-> Rules:
 a__2nd(cons(X,cons(Y,Z))) -> mark(Y)
 a__2nd(X) -> 2nd(X)
 a__from(X) -> cons(mark(X),from(s(X)))
 a__from(X) -> from(X)
 mark(2nd(X)) -> a__2nd(mark(X))
 mark(cons(X1,X2)) -> cons(mark(X1),X2)
 mark(from(X)) -> a__from(mark(X))
 mark(s(X)) -> s(mark(X))
->Strongly Connected Components:
 There is no strongly connected component

The problem is finite.