/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (2) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: active(g(X)) -> mark(h(X)) active(c) -> mark(d) active(h(d)) -> mark(g(c)) mark(g(X)) -> active(g(X)) mark(h(X)) -> active(h(X)) mark(c) -> active(c) mark(d) -> active(d) g(mark(X)) -> g(X) g(active(X)) -> g(X) h(mark(X)) -> h(X) h(active(X)) -> h(X) Q is empty. ---------------------------------------- (1) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 4. This implies Q-termination of R. The following rules were used to construct the certificate: active(g(X)) -> mark(h(X)) active(c) -> mark(d) active(h(d)) -> mark(g(c)) mark(g(X)) -> active(g(X)) mark(h(X)) -> active(h(X)) mark(c) -> active(c) mark(d) -> active(d) g(mark(X)) -> g(X) g(active(X)) -> g(X) h(mark(X)) -> h(X) h(active(X)) -> h(X) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 Node 1 is start node and node 2 is final node. Those nodes are connected through the following edges: * 1 to 3 labelled mark_1(0), active_1(0), active_1(1), mark_1(1)* 1 to 4 labelled mark_1(0)* 1 to 6 labelled active_1(0)* 1 to 5 labelled active_1(0)* 1 to 2 labelled g_1(0), h_1(0), g_1(1), h_1(1)* 1 to 7 labelled active_1(1), mark_1(1)* 1 to 8 labelled active_1(2)* 1 to 9 labelled mark_1(2)* 1 to 10 labelled mark_1(3), active_1(3)* 1 to 11 labelled active_1(4)* 2 to 2 labelled #_1(0)* 3 to 2 labelled h_1(0), d(0), h_1(1)* 4 to 5 labelled g_1(0)* 5 to 2 labelled c(0), c(1)* 6 to 2 labelled g_1(0), g_1(1)* 7 to 2 labelled h_1(1), d(1)* 7 to 5 labelled g_1(1)* 8 to 2 labelled h_1(2), d(2), h_1(1)* 8 to 5 labelled g_1(2)* 9 to 5 labelled h_1(2)* 10 to 5 labelled h_1(3)* 11 to 5 labelled h_1(4) ---------------------------------------- (2) YES