/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files


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YES

Problem:
 a(b(x1)) -> b(b(a(x1)))
 c(b(x1)) -> b(c(c(x1)))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [c](x0) = x0,
   
   [a](x0) = 8x0 + 1,
   
   [b](x0) = x0 + 1
  orientation:
   a(b(x1)) = 8x1 + 9 >= 8x1 + 3 = b(b(a(x1)))
   
   c(b(x1)) = x1 + 1 >= x1 + 1 = b(c(c(x1)))
  problem:
   c(b(x1)) -> b(c(c(x1)))
  KBO Processor:
   weight function:
    w0 = 1
    w(b) = 1
    w(c) = 0
   precedence:
    c > b
   problem:
    
   Qed