/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(a(d(d(x1)))) -> d(d(b(b(x1))))
 a(a(x1)) -> b(b(b(b(b(b(x1))))))
 b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1))))
 c(c(x1)) -> d(d(x1))

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [c](x0) = 2x0,
   
   [b](x0) = x0 + 1,
   
   [a](x0) = x0 + 5,
   
   [d](x0) = 2x0
  orientation:
   a(a(d(d(x1)))) = 4x1 + 10 >= 4x1 + 8 = d(d(b(b(x1))))
   
   a(a(x1)) = x1 + 10 >= x1 + 6 = b(b(b(b(b(b(x1))))))
   
   b(b(d(d(b(b(x1)))))) = 4x1 + 10 >= 4x1 + 10 = a(a(c(c(x1))))
   
   c(c(x1)) = 4x1 >= 4x1 = d(d(x1))
  problem:
   b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1))))
   c(c(x1)) -> d(d(x1))
  KBO Processor:
   weight function:
    w0 = 1
    w(c) = w(b) = w(d) = 1
    w(a) = 0
   precedence:
    a > c > b ~ d
   problem:
    
   Qed