/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> x1 a(b(x1)) -> b(a(c(x1))) b(x1) -> x1 c(c(x1)) -> b(a(x1)) Proof: String Reversal Processor: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) DP Processor: DPs: b#(a(x1)) -> b#(x1) b#(a(x1)) -> a#(b(x1)) b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) c#(c(x1)) -> a#(b(x1)) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) TDG Processor: DPs: b#(a(x1)) -> b#(x1) b#(a(x1)) -> a#(b(x1)) b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) c#(c(x1)) -> a#(b(x1)) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) graph: c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> c#(a(b(x1))) c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> a#(b(x1)) c#(c(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> a#(b(x1)) b#(a(x1)) -> c#(a(b(x1))) -> c#(c(x1)) -> b#(x1) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> c#(a(b(x1))) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> a#(b(x1)) b#(a(x1)) -> b#(x1) -> b#(a(x1)) -> b#(x1) SCC Processor: #sccs: 1 #rules: 3 #arcs: 8/25 DPs: c#(c(x1)) -> b#(x1) b#(a(x1)) -> b#(x1) b#(a(x1)) -> c#(a(b(x1))) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) interpretation: [c#](x0) = [0 3]x0 + [0], [b#](x0) = [3 0]x0 + [0], [0 0] [1] [c](x0) = [1 0]x0 + [0], [0 -&] [-&] [b](x0) = [1 0 ]x0 + [0 ], [1 0] [1] [a](x0) = [0 0]x0 + [1] orientation: c#(c(x1)) = [4 3]x1 + [3] >= [3 0]x1 + [0] = b#(x1) b#(a(x1)) = [4 3]x1 + [4] >= [3 0]x1 + [0] = b#(x1) b#(a(x1)) = [4 3]x1 + [4] >= [4 3]x1 + [4] = c#(a(b(x1))) [1 0] [1] a(x1) = [0 0]x1 + [1] >= x1 = x1 [1 0] [1] [1 0] [1] b(a(x1)) = [2 1]x1 + [2] >= [2 1]x1 + [2] = c(a(b(x1))) [0 -&] [-&] b(x1) = [1 0 ]x1 + [0 ] >= x1 = x1 [1 0] [1] [1 0] [1] c(c(x1)) = [1 1]x1 + [2] >= [1 0]x1 + [1] = a(b(x1)) problem: DPs: b#(a(x1)) -> c#(a(b(x1))) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) Restore Modifier: DPs: b#(a(x1)) -> c#(a(b(x1))) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) EDG Processor: DPs: b#(a(x1)) -> c#(a(b(x1))) TRS: a(x1) -> x1 b(a(x1)) -> c(a(b(x1))) b(x1) -> x1 c(c(x1)) -> a(b(x1)) graph: SCC Processor: #sccs: 0 #rules: 0 #arcs: 0/1