/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(b(a(a(a(a(a(a(a(x1)))))))))) -> a(a(a(a(a(a(a(a(b(b(a(a(b(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(a(b(b(a(x1)))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(a(a(b(b(a(x1)))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(a(a(b(b(x))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(a(a(b(b(x))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(a(a(b(b(x))))))))) -> b(b(a(a(b(b(a(a(a(a(a(a(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 7, 8, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122, 123, 124, 125, 126, 127, 128 Node 7 is start node and node 8 is final node. Those nodes are connected through the following edges: * 7 to 105 labelled b_1(0)* 8 to 8 labelled #_1(0)* 105 to 106 labelled b_1(0)* 106 to 107 labelled a_1(0)* 107 to 108 labelled a_1(0)* 108 to 109 labelled b_1(0)* 109 to 110 labelled b_1(0)* 110 to 111 labelled a_1(0)* 110 to 117 labelled b_1(1)* 111 to 112 labelled a_1(0)* 111 to 117 labelled b_1(1)* 112 to 113 labelled a_1(0)* 112 to 117 labelled b_1(1)* 113 to 114 labelled a_1(0)* 113 to 117 labelled b_1(1)* 114 to 115 labelled a_1(0)* 114 to 117 labelled b_1(1)* 115 to 116 labelled a_1(0)* 115 to 117 labelled b_1(1)* 116 to 8 labelled a_1(0)* 116 to 117 labelled b_1(1)* 117 to 118 labelled b_1(1)* 118 to 119 labelled a_1(1)* 119 to 120 labelled a_1(1)* 120 to 121 labelled b_1(1)* 121 to 122 labelled b_1(1)* 122 to 123 labelled a_1(1)* 122 to 117 labelled b_1(1)* 123 to 124 labelled a_1(1)* 123 to 117 labelled b_1(1)* 124 to 125 labelled a_1(1)* 124 to 117 labelled b_1(1)* 125 to 126 labelled a_1(1)* 125 to 117 labelled b_1(1)* 126 to 127 labelled a_1(1)* 126 to 117 labelled b_1(1)* 127 to 128 labelled a_1(1)* 127 to 117 labelled b_1(1)* 128 to 8 labelled a_1(1)* 128 to 117 labelled b_1(1) ---------------------------------------- (6) YES