/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files


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YES

Problem:
 a(x1) -> b(b(x1))
 b(b(b(x1))) -> a(x1)

Proof:
 Matrix Interpretation Processor: dim=1
  
  interpretation:
   [b](x0) = 3x0 + 1,
   
   [a](x0) = 9x0 + 4
  orientation:
   a(x1) = 9x1 + 4 >= 9x1 + 4 = b(b(x1))
   
   b(b(b(x1))) = 27x1 + 13 >= 9x1 + 4 = a(x1)
  problem:
   a(x1) -> b(b(x1))
  KBO Processor:
   weight function:
    w0 = 1
    w(a) = 1
    w(b) = 0
   precedence:
    b > a
   problem:
    
   Qed