/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> x1 a(x1) -> b(b(x1)) a(b(x1)) -> a(c(a(c(x1)))) c(c(x1)) -> x1 Proof: String Reversal Processor: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 DP Processor: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) b#(a(x1)) -> c#(a(x1)) b#(a(x1)) -> a#(c(a(x1))) b#(a(x1)) -> c#(a(c(a(x1)))) TRS: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 TDG Processor: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) b#(a(x1)) -> c#(a(x1)) b#(a(x1)) -> a#(c(a(x1))) b#(a(x1)) -> c#(a(c(a(x1)))) TRS: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 graph: b#(a(x1)) -> a#(c(a(x1))) -> a#(x1) -> b#(b(x1)) b#(a(x1)) -> a#(c(a(x1))) -> a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) -> b#(a(x1)) -> c#(a(c(a(x1)))) a#(x1) -> b#(b(x1)) -> b#(a(x1)) -> a#(c(a(x1))) a#(x1) -> b#(b(x1)) -> b#(a(x1)) -> c#(a(x1)) a#(x1) -> b#(x1) -> b#(a(x1)) -> c#(a(c(a(x1)))) a#(x1) -> b#(x1) -> b#(a(x1)) -> a#(c(a(x1))) a#(x1) -> b#(x1) -> b#(a(x1)) -> c#(a(x1)) SCC Processor: #sccs: 1 #rules: 3 #arcs: 8/25 DPs: b#(a(x1)) -> a#(c(a(x1))) a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) TRS: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 interpretation: [b#](x0) = [1 0]x0, [a#](x0) = [1 0]x0 + [0], [-& 0 ] [0] [c](x0) = [0 0 ]x0 + [0], [0 -&] [-&] [b](x0) = [1 0 ]x0 + [0 ], [2 1] [3] [a](x0) = [1 0]x0 + [0] orientation: b#(a(x1)) = [3 2]x1 + [4] >= [2 1]x1 + [3] = a#(c(a(x1))) a#(x1) = [1 0]x1 + [0] >= [1 0]x1 = b#(x1) a#(x1) = [1 0]x1 + [0] >= [1 0]x1 + [0] = b#(b(x1)) [2 1] [3] a(x1) = [1 0]x1 + [0] >= x1 = x1 [2 1] [3] [0 -&] [-&] a(x1) = [1 0]x1 + [0] >= [1 0 ]x1 + [0 ] = b(b(x1)) [2 1] [3] [2 1] [3] b(a(x1)) = [3 2]x1 + [4] >= [3 2]x1 + [4] = c(a(c(a(x1)))) [0 0] [0] c(c(x1)) = [0 0]x1 + [0] >= x1 = x1 problem: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) TRS: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 Restore Modifier: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) TRS: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 EDG Processor: DPs: a#(x1) -> b#(x1) a#(x1) -> b#(b(x1)) TRS: a(x1) -> x1 a(x1) -> b(b(x1)) b(a(x1)) -> c(a(c(a(x1)))) c(c(x1)) -> x1 graph: SCC Processor: #sccs: 0 #rules: 0 #arcs: 0/4