/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(x1)) -> b(d(x1)) a(c(x1)) -> d(d(d(x1))) b(d(x1)) -> a(c(b(x1))) c(f(x1)) -> d(d(c(x1))) d(d(x1)) -> f(x1) f(f(x1)) -> a(x1) Proof: Matrix Interpretation Processor: dim=1 interpretation: [f](x0) = x0 + 2, [c](x0) = x0, [d](x0) = x0 + 1, [a](x0) = x0 + 3, [b](x0) = 3x0 orientation: a(b(x1)) = 3x1 + 3 >= 3x1 + 3 = b(d(x1)) a(c(x1)) = x1 + 3 >= x1 + 3 = d(d(d(x1))) b(d(x1)) = 3x1 + 3 >= 3x1 + 3 = a(c(b(x1))) c(f(x1)) = x1 + 2 >= x1 + 2 = d(d(c(x1))) d(d(x1)) = x1 + 2 >= x1 + 2 = f(x1) f(f(x1)) = x1 + 4 >= x1 + 3 = a(x1) problem: a(b(x1)) -> b(d(x1)) a(c(x1)) -> d(d(d(x1))) b(d(x1)) -> a(c(b(x1))) c(f(x1)) -> d(d(c(x1))) d(d(x1)) -> f(x1) Matrix Interpretation Processor: dim=1 interpretation: [f](x0) = x0 + 2, [c](x0) = x0, [d](x0) = x0 + 1, [a](x0) = x0 + 8, [b](x0) = 8x0 orientation: a(b(x1)) = 8x1 + 8 >= 8x1 + 8 = b(d(x1)) a(c(x1)) = x1 + 8 >= x1 + 3 = d(d(d(x1))) b(d(x1)) = 8x1 + 8 >= 8x1 + 8 = a(c(b(x1))) c(f(x1)) = x1 + 2 >= x1 + 2 = d(d(c(x1))) d(d(x1)) = x1 + 2 >= x1 + 2 = f(x1) problem: a(b(x1)) -> b(d(x1)) b(d(x1)) -> a(c(b(x1))) c(f(x1)) -> d(d(c(x1))) d(d(x1)) -> f(x1) Bounds Processor: bound: 1 enrichment: match automaton: final states: {10,7,4,1} transitions: f50() -> 2* b0(2) -> 5* b0(3) -> 1* d0(2) -> 3* d0(9) -> 7* d0(8) -> 9* a0(6) -> 4* c0(5) -> 6* c0(2) -> 8* f0(2) -> 10* f1(25) -> 26* f1(19) -> 20* a1(17) -> 18* c1(16) -> 17* b1(15) -> 16* 2 -> 15* 4 -> 16,5 7 -> 8,19 8 -> 19* 9 -> 25* 10 -> 3* 18 -> 1* 20 -> 7* 26 -> 9* problem: Qed