/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(b(b(a(x1)))) -> a(c(a(b(x1)))) a(c(x1)) -> c(c(a(x1))) c(c(c(x1))) -> b(c(b(x1))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [c](x0) = [0 1 0]x0 [0 0 0] , [1 0 0] [b](x0) = [0 0 1]x0 [0 0 1] , [1 1 0] [0] [a](x0) = [0 0 0]x0 + [0] [0 0 1] [1] orientation: [1 1 1] [1] [1 0 1] [0] a(b(b(a(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(c(a(b(x1)))) [0 0 1] [2] [0 0 0] [1] [1 1 0] [0] [1 1 0] a(c(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 = c(c(a(x1))) [0 0 0] [1] [0 0 0] [1 0 0] [1 0 0] c(c(c(x1))) = [0 1 0]x1 >= [0 0 0]x1 = b(c(b(x1))) [0 0 0] [0 0 0] problem: a(c(x1)) -> c(c(a(x1))) c(c(c(x1))) -> b(c(b(x1))) Bounds Processor: bound: 1 enrichment: match automaton: final states: {5,1} transitions: f30() -> 2* c0(4) -> 1* c0(6) -> 7* c0(3) -> 4* a0(2) -> 3* b0(7) -> 5* b0(2) -> 6* b1(20) -> 21* b1(10) -> 11* b1(22) -> 23* b1(8) -> 9* c1(9) -> 10* c1(21) -> 22* 1 -> 3* 3 -> 20* 4 -> 8* 11 -> 1,3 23 -> 4* problem: Qed