/export/starexec/sandbox/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> b(x1) a(b(x1)) -> x1 b(a(x1)) -> a(c(a(b(x1)))) c(c(x1)) -> x1 Proof: String Reversal Processor: a(x1) -> b(x1) b(a(x1)) -> x1 a(b(x1)) -> b(a(c(a(x1)))) c(c(x1)) -> x1 DP Processor: DPs: a#(x1) -> b#(x1) a#(b(x1)) -> a#(x1) a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> b#(a(c(a(x1)))) TRS: a(x1) -> b(x1) b(a(x1)) -> x1 a(b(x1)) -> b(a(c(a(x1)))) c(c(x1)) -> x1 TDG Processor: DPs: a#(x1) -> b#(x1) a#(b(x1)) -> a#(x1) a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> b#(a(c(a(x1)))) TRS: a(x1) -> b(x1) b(a(x1)) -> x1 a(b(x1)) -> b(a(c(a(x1)))) c(c(x1)) -> x1 graph: a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> b#(a(c(a(x1)))) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(c(a(x1))) -> a#(b(x1)) -> a#(x1) a#(b(x1)) -> a#(c(a(x1))) -> a#(x1) -> b#(x1) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> b#(a(c(a(x1)))) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> c#(a(x1)) a#(b(x1)) -> a#(x1) -> a#(b(x1)) -> a#(x1) a#(b(x1)) -> a#(x1) -> a#(x1) -> b#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 10/25 DPs: a#(b(x1)) -> a#(c(a(x1))) a#(b(x1)) -> a#(x1) TRS: a(x1) -> b(x1) b(a(x1)) -> x1 a(b(x1)) -> b(a(c(a(x1)))) c(c(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> b(x1) b(a(x1)) -> x1 a(b(x1)) -> b(a(c(a(x1)))) c(c(x1)) -> x1 interpretation: [a#](x0) = [1 2]x0, [0 0 ] [0] [c](x0) = [0 -&]x0 + [0], [-& 0 ] [0] [b](x0) = [0 2 ]x0 + [3], [-& 0 ] [0] [a](x0) = [0 2 ]x0 + [3] orientation: a#(b(x1)) = [2 4]x1 + [5] >= [1 3]x1 + [4] = a#(c(a(x1))) a#(b(x1)) = [2 4]x1 + [5] >= [1 2]x1 = a#(x1) [-& 0 ] [0] [-& 0 ] [0] a(x1) = [0 2 ]x1 + [3] >= [0 2 ]x1 + [3] = b(x1) [0 2] [3] b(a(x1)) = [2 4]x1 + [5] >= x1 = x1 [0 2] [3] [0 2] [3] a(b(x1)) = [2 4]x1 + [5] >= [2 4]x1 + [5] = b(a(c(a(x1)))) [0 0] [0] c(c(x1)) = [0 0]x1 + [0] >= x1 = x1 problem: DPs: TRS: a(x1) -> b(x1) b(a(x1)) -> x1 a(b(x1)) -> b(a(c(a(x1)))) c(c(x1)) -> x1 Qed