/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(a(a(a(x1))))))))) -> a(a(a(a(a(a(b(a(b(a(b(x1))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(a(b(a(x1))))))))) -> b(a(b(a(b(a(a(a(a(a(a(x1))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(a(a(a(a(b(a(b(a(x1))))))))) -> b(a(b(a(b(a(a(a(a(a(a(x1))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(a(a(a(a(b(a(b(x)))))))) -> b(a(b(a(b(a(a(a(a(a(x)))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(a(a(a(a(b(a(b(x)))))))) -> b(a(b(a(b(a(a(a(a(a(x)))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(a(a(a(a(b(a(b(x)))))))) -> b(a(b(a(b(a(a(a(a(a(x)))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 475, 476, 477, 478, 479, 480, 481, 482, 483, 484, 485, 486, 487, 488, 489, 490, 491, 492, 493, 494 Node 475 is start node and node 476 is final node. Those nodes are connected through the following edges: * 475 to 477 labelled b_1(0)* 476 to 476 labelled #_1(0)* 477 to 478 labelled a_1(0)* 478 to 479 labelled b_1(0)* 479 to 480 labelled a_1(0)* 480 to 481 labelled b_1(0)* 481 to 482 labelled a_1(0)* 481 to 486 labelled b_1(1)* 482 to 483 labelled a_1(0)* 482 to 486 labelled b_1(1)* 483 to 484 labelled a_1(0)* 483 to 486 labelled b_1(1)* 484 to 485 labelled a_1(0)* 484 to 486 labelled b_1(1)* 485 to 476 labelled a_1(0)* 485 to 486 labelled b_1(1)* 486 to 487 labelled a_1(1)* 487 to 488 labelled b_1(1)* 488 to 489 labelled a_1(1)* 489 to 490 labelled b_1(1)* 490 to 491 labelled a_1(1)* 490 to 486 labelled b_1(1)* 491 to 492 labelled a_1(1)* 491 to 486 labelled b_1(1)* 492 to 493 labelled a_1(1)* 492 to 486 labelled b_1(1)* 493 to 494 labelled a_1(1)* 493 to 486 labelled b_1(1)* 494 to 476 labelled a_1(1)* 494 to 486 labelled b_1(1) ---------------------------------------- (6) YES