/export/starexec/sandbox2/solver/bin/starexec_run_ttt2-1.17+nonreach /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem: a(x1) -> x1 a(b(b(x1))) -> b(b(a(b(c(a(x1)))))) b(c(x1)) -> x1 Proof: DP Processor: DPs: a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> b#(c(a(x1))) a#(b(b(x1))) -> a#(b(c(a(x1)))) a#(b(b(x1))) -> b#(a(b(c(a(x1))))) a#(b(b(x1))) -> b#(b(a(b(c(a(x1)))))) TRS: a(x1) -> x1 a(b(b(x1))) -> b(b(a(b(c(a(x1)))))) b(c(x1)) -> x1 TDG Processor: DPs: a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> b#(c(a(x1))) a#(b(b(x1))) -> a#(b(c(a(x1)))) a#(b(b(x1))) -> b#(a(b(c(a(x1))))) a#(b(b(x1))) -> b#(b(a(b(c(a(x1)))))) TRS: a(x1) -> x1 a(b(b(x1))) -> b(b(a(b(c(a(x1)))))) b(c(x1)) -> x1 graph: a#(b(b(x1))) -> a#(b(c(a(x1)))) -> a#(b(b(x1))) -> b#(b(a(b(c(a(x1)))))) a#(b(b(x1))) -> a#(b(c(a(x1)))) -> a#(b(b(x1))) -> b#(a(b(c(a(x1))))) a#(b(b(x1))) -> a#(b(c(a(x1)))) -> a#(b(b(x1))) -> a#(b(c(a(x1)))) a#(b(b(x1))) -> a#(b(c(a(x1)))) -> a#(b(b(x1))) -> b#(c(a(x1))) a#(b(b(x1))) -> a#(b(c(a(x1)))) -> a#(b(b(x1))) -> a#(x1) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> b#(b(a(b(c(a(x1)))))) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> b#(a(b(c(a(x1))))) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> a#(b(c(a(x1)))) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> b#(c(a(x1))) a#(b(b(x1))) -> a#(x1) -> a#(b(b(x1))) -> a#(x1) SCC Processor: #sccs: 1 #rules: 2 #arcs: 10/25 DPs: a#(b(b(x1))) -> a#(b(c(a(x1)))) a#(b(b(x1))) -> a#(x1) TRS: a(x1) -> x1 a(b(b(x1))) -> b(b(a(b(c(a(x1)))))) b(c(x1)) -> x1 Arctic Interpretation Processor: dimension: 2 usable rules: a(x1) -> x1 a(b(b(x1))) -> b(b(a(b(c(a(x1)))))) b(c(x1)) -> x1 interpretation: [a#](x0) = [-& 2 ]x0 + [0], [-& -&] [0] [c](x0) = [0 0 ]x0 + [2], [-& 0 ] [3 ] [b](x0) = [2 0 ]x0 + [-&], [0 0] [0] [a](x0) = [0 0]x0 + [0] orientation: a#(b(b(x1))) = [4 4]x1 + [7] >= [2 2]x1 + [4] = a#(b(c(a(x1)))) a#(b(b(x1))) = [4 4]x1 + [7] >= [-& 2 ]x1 + [0] = a#(x1) [0 0] [0] a(x1) = [0 0]x1 + [0] >= x1 = x1 [2 2] [5] [2 2] [5] a(b(b(x1))) = [2 2]x1 + [5] >= [2 2]x1 + [5] = b(b(a(b(c(a(x1)))))) [0 0] [3] b(c(x1)) = [0 0]x1 + [2] >= x1 = x1 problem: DPs: TRS: a(x1) -> x1 a(b(b(x1))) -> b(b(a(b(c(a(x1)))))) b(c(x1)) -> x1 Qed