/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(b(a(a(b(a(b(a(x1)))))))))))) -> a(a(b(a(b(a(a(b(a(b(a(b(a(b(x1)))))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(b(a(x1)))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(a(x1)))))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(a(b(a(a(b(a(b(a(b(a(x1)))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(a(x1)))))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(a(b(a(a(b(a(b(a(b(x))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(x))))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(a(b(a(a(b(a(b(a(b(x))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(x))))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(a(b(a(a(b(a(b(a(b(x))))))))))) -> b(a(b(a(b(a(b(a(a(b(a(b(a(x))))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 539, 540, 567, 568, 569, 570, 571, 572, 573, 574, 575, 576, 577, 578, 579, 580, 581, 582, 583, 584, 585, 586, 587, 588, 589, 590 Node 539 is start node and node 540 is final node. Those nodes are connected through the following edges: * 539 to 567 labelled b_1(0)* 540 to 540 labelled #_1(0)* 567 to 568 labelled a_1(0)* 568 to 569 labelled b_1(0)* 569 to 570 labelled a_1(0)* 569 to 579 labelled b_1(1)* 570 to 571 labelled b_1(0)* 571 to 572 labelled a_1(0)* 572 to 573 labelled b_1(0)* 573 to 574 labelled a_1(0)* 574 to 575 labelled a_1(0)* 574 to 579 labelled b_1(1)* 575 to 576 labelled b_1(0)* 576 to 577 labelled a_1(0)* 576 to 579 labelled b_1(1)* 577 to 578 labelled b_1(0)* 578 to 540 labelled a_1(0)* 578 to 579 labelled b_1(1)* 579 to 580 labelled a_1(1)* 580 to 581 labelled b_1(1)* 581 to 582 labelled a_1(1)* 581 to 579 labelled b_1(1)* 582 to 583 labelled b_1(1)* 583 to 584 labelled a_1(1)* 584 to 585 labelled b_1(1)* 585 to 586 labelled a_1(1)* 586 to 587 labelled a_1(1)* 586 to 579 labelled b_1(1)* 587 to 588 labelled b_1(1)* 588 to 589 labelled a_1(1)* 588 to 579 labelled b_1(1)* 589 to 590 labelled b_1(1)* 590 to 540 labelled a_1(1)* 590 to 579 labelled b_1(1) ---------------------------------------- (6) YES