/export/starexec/sandbox2/solver/bin/starexec_run_standard /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRS Reverse [EQUIVALENT, 0 ms] (2) QTRS (3) Strip Symbols Proof [SOUND, 0 ms] (4) QTRS (5) RFCMatchBoundsTRSProof [EQUIVALENT, 0 ms] (6) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(c(b(a(b(a(c(b(a(x1))))))))) -> a(b(a(c(b(a(c(b(a(b(a(c(x1)))))))))))) Q is empty. ---------------------------------------- (1) QTRS Reverse (EQUIVALENT) We applied the QTRS Reverse Processor [REVERSE]. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(a(b(a(b(c(a(x1))))))))) -> c(a(b(a(b(c(a(b(c(a(b(a(x1)))))))))))) Q is empty. ---------------------------------------- (3) Strip Symbols Proof (SOUND) We were given the following TRS: a(b(c(a(b(a(b(c(a(x1))))))))) -> c(a(b(a(b(c(a(b(c(a(b(a(x1)))))))))))) By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: a(b(c(a(b(a(b(c(x)))))))) -> c(a(b(a(b(c(a(b(c(a(b(x))))))))))) ---------------------------------------- (4) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: a(b(c(a(b(a(b(c(x)))))))) -> c(a(b(a(b(c(a(b(c(a(b(x))))))))))) Q is empty. ---------------------------------------- (5) RFCMatchBoundsTRSProof (EQUIVALENT) Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. The following rules were used to construct the certificate: a(b(c(a(b(a(b(c(x)))))))) -> c(a(b(a(b(c(a(b(c(a(b(x))))))))))) The certificate found is represented by the following graph. The certificate consists of the following enumerated nodes: 4, 8, 73, 74, 75, 77, 78, 80, 82, 84, 86, 88, 93, 94, 95, 96, 97, 98, 99, 100, 101, 102 Node 4 is start node and node 8 is final node. Those nodes are connected through the following edges: * 4 to 73 labelled c_1(0)* 8 to 8 labelled #_1(0)* 73 to 74 labelled a_1(0)* 74 to 75 labelled b_1(0)* 75 to 77 labelled a_1(0)* 77 to 78 labelled b_1(0)* 78 to 80 labelled c_1(0)* 80 to 82 labelled a_1(0)* 80 to 93 labelled c_1(1)* 82 to 84 labelled b_1(0)* 84 to 86 labelled c_1(0)* 86 to 88 labelled a_1(0)* 86 to 93 labelled c_1(1)* 88 to 8 labelled b_1(0)* 93 to 94 labelled a_1(1)* 94 to 95 labelled b_1(1)* 95 to 96 labelled a_1(1)* 96 to 97 labelled b_1(1)* 97 to 98 labelled c_1(1)* 98 to 99 labelled a_1(1)* 98 to 93 labelled c_1(1)* 99 to 100 labelled b_1(1)* 100 to 101 labelled c_1(1)* 101 to 102 labelled a_1(1)* 101 to 93 labelled c_1(1)* 102 to 8 labelled b_1(1) ---------------------------------------- (6) YES