/export/starexec/sandbox2/solver/bin/starexec_run_default /export/starexec/sandbox2/benchmark/theBenchmark.xml /export/starexec/sandbox2/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x x' y y' z) (RULES fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' ) Problem 1: Valid CTRS Processor: -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: FIB(s(x)) -> PLUS(y,z) | fib(x) -> pair(y,z) PLUS(x,y) -> PLUS(x',y') | x -> s(x'), y -> y' -> QPairs: Empty -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' Conditional Termination Problem 2: -> Pairs: FIB(s(x)) -> FIB(x) -> QPairs: FIB(s(x)) -> PLUS(y,z) | fib(x) -> pair(y,z) PLUS(x,y) -> PLUS(x',y') | x -> s(x'), y -> y' -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' The problem is decomposed in 2 subproblems. Problem 1.1: SCC Processor: -> Pairs: FIB(s(x)) -> PLUS(y,z) | fib(x) -> pair(y,z) PLUS(x,y) -> PLUS(x',y') | x -> s(x'), y -> y' -> QPairs: Empty -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: PLUS(x,y) -> PLUS(x',y') | x -> s(x'), y -> y' ->->-> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' Problem 1.1: Reduction Triple Processor: -> Pairs: PLUS(x,y) -> PLUS(x',y') | x -> s(x'), y -> y' -> QPairs: Empty -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' -> Usable rules: Empty ->Interpretation type: Linear ->Coefficients: Integer Numbers ->Dimension: 1 ->Convex Domain: D[(x_1)] = ((-1+x_1 >= 0) /\ (0 >= 0)) ->Interpretation: [delta] = 1 [s](x_1) = 1+x_1 [PLUS](x_1,x_2) = x_1 Problem 1.1: SCC Processor: -> Pairs: Empty -> QPairs: Empty -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: SCC Processor: -> Pairs: FIB(s(x)) -> FIB(x) -> QPairs: FIB(s(x)) -> PLUS(y,z) | fib(x) -> pair(y,z) PLUS(x,y) -> PLUS(x',y') | x -> s(x'), y -> y' -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: FIB(s(x)) -> FIB(x) ->->-> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' Problem 1.2: Conditional Subterm Processor: -> Pairs: FIB(s(x)) -> FIB(x) -> QPairs: Empty -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' ->Projection: pi(FIB) = 1 Problem 1.2: SCC Processor: -> Pairs: Empty -> QPairs: Empty -> Rules: fib(0) -> pair(0,s(0)) fib(s(x)) -> pair(z,plus(y,z)) | fib(x) -> pair(y,z) plus(x,y) -> s(plus(x',y')) | x -> s(x'), y -> y' plus(x,y) -> y' | x -> 0, y -> y' ->Strongly Connected Components: There is no strongly connected component The problem is finite.