/export/starexec/sandbox/solver/bin/starexec_run_default /export/starexec/sandbox/benchmark/theBenchmark.xml /export/starexec/sandbox/output/output_files -------------------------------------------------------------------------------- YES Problem 1: (VAR x y) (RULES a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ) Problem 1: Valid CTRS Processor: -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c -> The system is a deterministic 3-CTRS. Problem 1: Dependency Pairs Processor: Conditional Termination Problem 1: -> Pairs: G(x,b) -> F(c) | f(b) -> x, x -> c G(x,b) -> G(f(c),x) | f(b) -> x, x -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c Conditional Termination Problem 2: -> Pairs: F(x) -> A G(x,b) -> F(b) -> QPairs: G(x,b) -> F(c) | f(b) -> x, x -> c G(x,b) -> G(f(c),x) | f(b) -> x, x -> c -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c The problem is decomposed in 2 subproblems. Problem 1.1: SCC Processor: -> Pairs: G(x,b) -> F(c) | f(b) -> x, x -> c G(x,b) -> G(f(c),x) | f(b) -> x, x -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G(x,b) -> G(f(c),x) | f(b) -> x, x -> c ->->-> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c Problem 1.1: Simplification and Narrowing on Condition Processor: -> Pairs: G(x,b) -> G(f(c),x) | f(b) -> x, x -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Narrowed Pairs: ->->Original Pair: G(x,b) -> G(f(c),x) | f(b) -> x, x -> c ->-> Narrowed pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(b), b -> x2, x2 -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c Problem 1.1: SCC Processor: -> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(b), b -> x2, x2 -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(b), b -> x2, x2 -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c ->->-> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c Problem 1.1: Reduction Triple Processor: -> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(b), b -> x2, x2 -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c -> Usable rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) ->Interpretation type: Linear ->Coefficients: Integer Numbers ->Dimension: 1 ->Convex Domain: D[(x_1)] = ((1+x_1 >= 0) /\ (0 >= 0)) ->Interpretation: [delta] = 1 [a] = 1 [f](x_1) = 1 [b] = -1 [c] = 0 [h](x_1) = 1+x_1 [G](x_1,x_2) = 0 Problem 1.1: SCC Processor: -> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c ->->-> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c Problem 1.1: Reduction Triple Processor: -> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c G(x2,b) -> G(f(c),x2) | a -> h(c), c -> x2, x2 -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c -> Usable rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) ->Interpretation type: Linear ->Coefficients: Integer Numbers ->Dimension: 1 ->Convex Domain: D[(x_1)] = ((1+x_1 >= 0) /\ (-x_1 >= 0)) ->Interpretation: [delta] = 1 [a] = 0 [f](x_1) = 0 [b] = 0 [c] = -1 [h](x_1) = x_1 [G](x_1,x_2) = x_2 Problem 1.1: SCC Processor: -> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c ->->-> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c Problem 1.1: Reduction Triple Processor: -> Pairs: G(f(b),b) -> G(f(c),f(b)) | f(b) -> c -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c -> Usable rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) ->Interpretation type: Linear ->Coefficients: Integer Numbers ->Dimension: 1 ->Convex Domain: D[(x_1)] = ((x_1 >= 0) /\ (0 >= 0)) ->Interpretation: [delta] = 1 [a] = 1 [f](x_1) = 1+x_1 [b] = 1 [c] = 0 [h](x_1) = x_1 [G](x_1,x_2) = 2.x_1+x_2 Problem 1.1: SCC Processor: -> Pairs: Empty -> QPairs: Empty -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Strongly Connected Components: There is no strongly connected component The problem is finite. Problem 1.2: SCC Processor: -> Pairs: F(x) -> A G(x,b) -> F(b) -> QPairs: G(x,b) -> F(c) | f(b) -> x, x -> c G(x,b) -> G(f(c),x) | f(b) -> x, x -> c -> Rules: a -> h(b) a -> h(c) f(x) -> y | a -> h(y) g(x,b) -> g(f(c),x) | f(b) -> x, x -> c ->Strongly Connected Components: There is no strongly connected component The problem is finite.